I believe the correct answer is 1 solution
Step-by-step explanation:

According to this trigonometric function, −C gives you the OPPOSITE terms of what they really are, so be EXTREMELY CAREFUL:
![\displaystyle Phase\:[Horisontal]\:Shift → \frac{0}{4} = 0 \\ Period → \frac{2}{4}π = \frac{π}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7B0%7D%7B4%7D%20%3D%200%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7B4%7D%CF%80%20%3D%20%5Cfrac%7B%CF%80%7D%7B2%7D)
Therefore we have our answer.
Extended Information on the trigonometric function
![\displaystyle Vertical\:Shift → D \\ Phase\:[Horisontal]\:Shift → \frac{C}{B} \\ Period → \frac{2}{B}π \\ Amplitude → |A|](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Vertical%5C%3AShift%20%E2%86%92%20D%20%5C%5C%20Phase%5C%3A%5BHorisontal%5D%5C%3AShift%20%E2%86%92%20%5Cfrac%7BC%7D%7BB%7D%20%5C%5C%20Period%20%E2%86%92%20%5Cfrac%7B2%7D%7BB%7D%CF%80%20%5C%5C%20Amplitude%20%E2%86%92%20%7CA%7C)
NOTE: Sometimes, your <em>vertical shift</em> might tell you to shift your graph below or above the <em>midline</em> where the amplitude is. Moreover, ALL <em>tangent</em>,<em> </em><em>secant</em>, <em>cosecant</em>, and <em>cotangent</em> functions have NO AMPLITUDE.
I am joyous to assist you anytime.
is the equation in the question written like the one in the bottom? Because for me to help you I must confirm what the equation looks like.
× 
Answer:
Step-by-step explanation:
<u>Sum of the interior angles of a regular polygon:</u>
- S(n) = 180°(n - 2), where n- number of sides
<h3>Exercise 4</h3>
<u>Pentagon has sum of angles:</u>
- S(5) = 180°(5 - 2) = 540°
<u>Sum the given angles and find x:</u>
- x° + 122° + 100° + 90° + 144° = 540°
- x° + 456° = 540°
- x° = 540° - 456°
- x° = 84°
<h3>Exercise 5</h3>
<u>Hexagon has sum of angles:</u>
- S(6) = 180°(6 - 2) = 720°
<u>Sum the given angles and find x:</u>
- x° + 110° + 160° + 105° + 105° + 115° = 720°
- x° + 595° = 720°
- x° = 720° - 595°
- x° = 125°
Answer:
what line? I don't see a picture.