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Pani-rosa [81]
3 years ago
11

A solution of salt and water contains 70 grams of water per 140 milliliters of the solution. if 1 mole of water weighs 16 grams,

2.19 moles of water would be present in 35 milliliters of the solution. [round off your answer to two decimal places. if you answer is less than one, include the zero before the decimal point.]
Mathematics
1 answer:
Fynjy0 [20]3 years ago
6 0
Be present in 35 milliliters of the solution. [round off your answer to two decimal places. if you answer is less than one, include the zero before the decimal point.]

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Please help me, you will get 20 points:)
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Dont listen to the person above, they put the same link everhwher
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3 years ago
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An aircraft factory manufactures airplane engines. The unit cost C (the cost in dollars to make each airplane engine) depends on
butalik [34]

Answer:

90 engines must be made to minimize the unit cost.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

f(x) = ax^{2} + bx + c

It's vertex is the point (x_{v}, y_{v})

In which

x_{v} = -\frac{b}{2a}

y_{v} = -\frac{\Delta}{4a}

Where

\Delta = b^2-4ac

If a>0, the minimum value of the function will happen for x = x_v

C(x)=x²-180x+20,482

This means that a = 1, b = -180, c = 20482

How many engines must be made to minimize the unit cost?

x value of the vertex. So

x_{v} = -\frac{b}{2a} = -\frac{-180}{2(1)} = 90

90 engines must be made to minimize the unit cost.

3 0
3 years ago
What is the horizontal asymptote for y(t) for the differential equation dy dt equals the product of 2 times y and the quantity 1
marta [7]
First, we need to solve the differential equation.
\frac{d}{dt}\left(y\right)=2y\left(1-\frac{y}{8}\right)
This a separable ODE. We can rewrite it like this:
-\frac{4}{y^2-8y}{dy}=dt
Now we integrate both sides.
\int \:-\frac{4}{y^2-8y}dy=\int \:dt
We get:
\frac{1}{2}\ln \left|\frac{y-4}{4}+1\right|-\frac{1}{2}\ln \left|\frac{y-4}{4}-1\right|=t+c_1
When we solve for y we get our solution:
y=\frac{8e^{c_1+2t}}{e^{c_1+2t}-1}
To find out if we have any horizontal asymptotes we must find the limits as x goes to infinity and minus infinity. 
It is easy to see that when x goes to minus infinity our function goes to zero.
When x goes to plus infinity we have the following:
$$\lim_{x\to\infty} f(x)$$=y=\frac{8e^{c_1+\infty}}{e^{c_1+\infty}-1} = 8
When you are calculating limits like this you always look at the fastest growing function in denominator and numerator and then act like they are constants. 
So our asymptote is at y=8.

3 0
3 years ago
URGENT!! DUE IN 15 MIN!!<br> *don't mind the answer I chose*
prisoha [69]
I think its D but im not sure
8 0
3 years ago
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Terry is feeling crafty and wants to put a ribbon border on her boring clock to jazz it up a bit. If the clock has a radius of 1
Sunny_sXe [5.5K]
Given radius=15 inches
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