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Gre4nikov [31]
3 years ago
10

Evaluate x(-9)+2y when x=4, y=-1

Mathematics
2 answers:
diamong [38]3 years ago
8 0

(4)(-9) + 2 (-1) = - 38

....................................

pshichka [43]3 years ago
6 0

Answer:

= -39

Step-by-step explanation:

x(-9)+2y = -9x + 2y

if:

x = 4

y = -1

then:

-9*4 + 2*-1

-36 - 3

-39

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I need an equation that has variables on both sides were x = 17
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Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa
Nataly_w [17]

Answer:

The first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

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Step-by-step explanation:

(2+x)^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})

= 6_{C_{0}} \times x^{0} \times 2^{6}  + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4} + terms involving higher powers of x

= 64 + 192 \times x^{1} + 240 \times x^{2} + terms involving higher powers of x

so, the first 3 terms in the expansion of (2 + x)^{6} , in ascending power of x are,

64 , 192 \times x^{1} {\textrm{  and  }}240 \times x^{2}

Again,

(2+x - x^{2})^{6}

= \sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})

Now, by inspection,

the term x^{2} comes from k =5 and k = 6

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so,   coefficient of x^{2} in the final expression = (240 - 192) = 48

3 0
3 years ago
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