I don't know. This seems tricky. But I do know that the probability would be 1 divided by the probability. So A and D is Incorrect. Theres never really a 50-50 chance with Locker doors so I'm gonna go with C.
I'm not guaranteed this is the answer. But I do Hope it helps. =)
Answer:
All points on line CD are equidistant from A and B
Step-by-step explanation:
Given that point A is the center of circle A and point B is the center of circle B, and the circumference of circle A passes through the center of circle B which is point B and vice versa.
Therefore we have;
The radius of circle A = The radius of circle B
Which gives;
The distance of the point C to the center A is equal to the distance of the point C to the center B
Similarly, the distance of the point D to the center A is equal to the distance of the point D to the center B
So also the distances of all points on the line from the center A is equal to the distances of all points on the line from the center B.
There are no numbers that are both prime and square.
In addition, only one prime number is even, which is 2.
Answer:
Step-by-step explanation:
