All categories

4 years ago

Equation of perpendicular line: Equation of parallel line:

Mathematics

1 answer:

tamaranim1 [39]4 years ago

8 0

1)Parallel means they have to have the same slope. Since our equation is y=2/3x+1, a line parallel to that would be(using out points) -5=2/3(-4)+b.

To find the y-intercept, solve for "b".

b=-7/3

Our equation would then be y=2/3x-7/3

2)Perpendicular lines have opposite-reciprocal slopes. our previous equation was y=2/3x+1, so our new equation would be -5=-3/2(-4)+b. Now lets solve for b.

b=-11

So our perpendicular equation would be y=-3/2x-11

Hope that was helpful. :)

You might be interested in

Find three positive numbers whose sum is 12 and the sum of whose squares is as small as possible.

denis-greek [22]

Answer:

4, 4, and 4.

8 0

3 years ago

Read 2 more answers

Rearranging formula

allochka39001 [22]

Answer:

Arlo's weight = 52.3 kg

Explanation:

Let Arlo be "x"

Then,

Arlo = x

Bert = x+20 (Because Bert is 20 heavier than Arlo)

Cassie = x+20-5 (Because Cassie is 5 lighter than Bert)

Donnie = $\frac{x+20}{2}$ (Because Donnie is half of Bert's weight)

Average = 57

Step by step Calculations:

57 = $\frac{(x) + (x+20) + (x+20-5) + (\frac{x+20}{2} )}{4}$ (The whole divided by 4 because the total people is 4)

57*4 = x + x + 20 + x + 20 - 5 + $\frac{x+20}{2}$

228 = 3x + 35 + $\frac{x+20}{2}$

228 - 3x - 35 = $\frac{x+20}{2}$

193 -3x = $\frac{x+20}{2}$

2(193 - 3x) = x + 20

386 - 6x = x + 20

386 - 20 = x + 6x

366 = 7x

x = $\frac{366}{7}$

x = 52.3 kg (corrected to 3 significant figures)

Therefore Arlo's weight is 52.3 kg

8 0

3 years ago

Given right triangle ABC with altitude BD is drawn to hypotenuse AC. If AB=5 and AD=1, what is the length of AC ? (Note: the fig

Alex17521 [72]

Answer:

x = 24.99 or 25

Step-by-step explanation:

Using sin to figure out the angle of ABD, we can figure out the angle of CBD by subtracting it from 90°.

sin y = (1/5)

y = 11.54°

90 - 11.54 = 78.46°

Now using Pythagorean Theorem (a²+b²=c²) we can solve for line BD.

1² + b² = 5²

1 + b² = 25

b² = 24

b = √24

Now we can use tan to figure out the length of segment DC.

tan(78.46) = z/√24

z = 23.99

We can now combine the known length of segment AD and the length of DC to get x.

1 + 23.99 = 24.99 or about 25.

8 0

3 years ago

Sum term product factor quotients coefficients for 5x+12

Svetllana [295]

I tried I hope this helps in any kind of way

4 0

3 years ago

Who knows this, Find m∠UTS, if m∠UTV=x+15, m∠VTS=140∘, and m∠UTS=15x+15

kakasveta [241]

Answer:

165

Step-by-step explanation:

First, m<UTS=m<UTV+m<VTS by Angle Addition Postulate. Then, you substitute all the values that you provided for the angles. 15x+15=x+15+140. You then solve for x.

15x+15=x+155

14x=140

x=10

You then plug back in 10 for X in the value of m<UTS. 15(10)+15=165

5 0

3 years ago