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4 years ago

8

Find two consecutive even integers such that the lesser added to three times the greater gives a sum of 46.

1 answer:

kvv77 [185]4 years ago

5 0

N; n + 2 - the two consecutive even integers

n + 3(n + 2) = 46
n + 3n + 6 = 46 <em> |subtract 6 from both sides</em>
4n = 40 <em> |divide both sides by 4</em>
n = 10

n + 2 = 10 + 2 = 12

<u>Answer: 10 and 12.</u>

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