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A sphere of radius 3 is inscribed in a cylinder. What is the volume inside the cylinder but not inside the sphere?
1 answer:
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Answer:
3x+y=8 and 3x+y=9
Step-by-step explanation:
Assume these two equations:
a1x+b1y+c1=0
a2x+b2y+c2=0
If (a1/a2) = (b1/b2) ≠ (c1/c2) than those two would have no solution.
In these case, take a look at the last option:
Re-write 'em as a standard form:
So (a1/a2) = (b1/b2) ≠ (c1/c2) is true here:
And they do not have any collision point
Answer:
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.
Step-by-step explanation:
The height h of the ball is modeled by the following equation
The problem want you to find the times the ball will be 48 feet above the ground.
It is going to be when:
We can simplify by 16t. So
It means that
16t = 0
t = 0
or
t - 2 = 0
t = 2
So, the times the ball will be 48 feet above the ground are t = 0 and t = 2.