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3 years ago

The third segment in the graph is not as step as the segment. what does this mean?

Mathematics

1 answer:

Tomtit [17]3 years ago

4 0

in geometry a line segment part of a line that is bounded by two distinct endpoints

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Simplify the expression- 3 - 5/6 / 5/2

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Answer:

10/3

Step-by-step explanation:

-3-5/6/5/2=-10/3

decimal 0.33333 reaccuring

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3 years ago

Using fluorescent imaging techniques, researchers observed that the position of binding sites on HIV peptides is approximately N

konstantin123 [22]

Answer:

The values is

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 2.45$

The standard deviation is $\sigma = 0.35 \ mi$

The random value is $x = 2.03$

The standardized score for a binding site position of 2.03 microns is mathematically represented as

$z-score = \frac{x - \mu}{ \sigma }$

=> $z-score = \frac{2.03 - 2.45}{ 0.35}$

=> $z-score = -1.2$

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3 years ago

What is the difference between rigid and nonrigid transformations?

never [62]

Answer:

The rigid transformation, which does not change the shape or size of the preimage. The non-rigid transformation, which will change the size but not the shape of the preimage.

Step-by-step explanation:

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3 years ago

On Saturday, 960 people visit the zoo. Of the visitors, 40% are children. How many of the visitors on Saturday were children?

MatroZZZ [7]

384 people that visited were children

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3 years ago

What is the exact value of sin(theta + beta)?

NISA [10]

Answer: $\frac{-3\sqrt{13}+4\sqrt{3}}{20}$

This is the single fraction of -3*sqrt(13)+4*sqrt(3) up top all over 20.

sqrt = square root

=======================================================

Explanation:

Angle theta is between pi and 3pi/2. This places the angle in quadrant Q3 where both cosine and sine are negative

Use the pythagorean trig identity to get the following:

$\sin^2 \theta + \cos^2 \theta = 1\\\\\sin^2 \theta + \left(-\frac{\sqrt{3}}{4}\right)^2 = 1\\\\\sin^2 \theta + \frac{3}{16} = 1\\\\\sin^2 \theta = 1 - \frac{3}{16}\\\\\sin^2 \theta = \frac{16}{16} - \frac{3}{16}\\\\\sin^2 \theta = \frac{16-3}{16}\\\\\sin^2 \theta = \frac{13}{16}\\\\\sin \theta = -\sqrt{\frac{13}{16}} \ \text{ ... sine is negative in Q3}\\\\\sin \theta = -\frac{\sqrt{13}}{\sqrt{16}}\\\\\sin \theta = -\frac{\sqrt{13}}{4}\\\\$

Angle beta is in Q1 where sine and cosine are positive.

Draw a right triangle with legs 3 and 4. The hypotenuse is 5 through the pythagorean theorem. In other words, we have a 3-4-5 right triangle.

Since $\tan \beta = \frac{3}{4}$ , this means $\sin \beta = \frac{3}{5} \ \text{ and } \ \cos \beta = \frac{4}{5}$

Use these ideas:

sin = opposite/hypotenuse
cos = adjacent/hypotenuse
tan = opposite/adjacent

In this case we have: opposite = 3, adjacent = 4, hypotenuse = 5.

-------------------------------------

To recap:

$\cos \theta = -\frac{\sqrt{3}}{4}\\\\\sin \theta = -\frac{\sqrt{13}}{4}\\\\\cos \beta = \frac{3}{5}\\\\\sin \beta = \frac{4}{5}\\\\$

They lead to this

$\sin\left(\theta + \beta\right) = \sin \theta * \cos \beta - \cos \theta * \sin \beta\\\\\sin\left(\theta + \beta\right) = -\frac{\sqrt{13}}{4} * \frac{3}{5} - \left(-\frac{\sqrt{3}}{4}\right) * \frac{4}{5}\\\\\sin\left(\theta + \beta\right) = -\frac{3\sqrt{13}}{20}+\frac{4\sqrt{3}}{20}\\\\\sin\left(\theta + \beta\right) = \frac{-3\sqrt{13}+4\sqrt{3}}{20}\\\\$

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2 years ago

The third segment in the graph is not as step as the segment. what does this mean? ​

The third segment in the graph is not as step as the segment. what does this mean?