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3 years ago

I WILL MARK YOU BRAINLIEST!PLEASE SOLVE FOR X

Mathematics

2 answers:

polet [3.4K]3 years ago

4 0

Answer and Step-by-step explanation:

We see that the bottom two lines are parallel, which makes angle x and angle 5 "same-side corresponding angles". By definition, same-side corresponding angles are congruent. That means angle x = angle 5.

Note that you didn't provide any measures, so it is impossible to actually figure out an exact degree. However, angle x is the same degree as angle 5.

Hope this helps!

ryzh [129]3 years ago

3 0

Answer:

Angle x = Angle 5

Step-by-step explanation:

Angle x = Angle 5

Because they are corresponding angles on parallel lines

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The mad scientist will need one-third of the eyeball how many eyeball is that

aliina [53]

Answer:

1/3

Step-by-step explanation:

The mad scientist needs one-third or 1/3 of the eyeball.

That is 1/3 of the eyeball.

5 0

3 years ago

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Someone please help me in this question it is kind of confusing it is a question under pre calculus in first year calculus i wil

masya89 [10]

Neither P, nor A are on the sketch
I guess P is the upper right corner of the rectangle
and A=(0,1)

P belongs to the line going through (1,0) and B(0,y)
but we don't know the y-coordinate of B 

the triangle is right and isosceles, so pythagoras a²+a²=2² ... 2a²=4 ... a²=2 ... a=sqrt2 
now look at the right triangle BOA
his hypotenuse is AB=sqrt2 and the the kathete OA is 1 
so y²+1²=(sqrt2)² ... y²+1=2 ... y²=1.. y=1
so the coordinates of B are (0,1)

the line going through (1,0) and (0,1) is L(x)=-x+1

P belongs to this line, so the coordinates of P are P(x,-x+1) (0<x<1)

b) so if that's P, the height of the rectangle is -x+1 and the width=2x
so its area A(x)=2x*(-x+1)= -2x²+2x

I hope my answer has come to your help. Thank you for posting your question here in Brainly.

5 0

3 years ago

The table represents an exponential function.

Stels [109]

The exponential function is given in the form

$y= a (b)^{x}$

where a is the initial value and b is the multiplicative rate of change

So lets plug the first two values of the table in this function , we get

$2= a(b)^1$

$2= ab............................(eqn 1)$

Now plug second

$2/5 = a(b)^2 .............................( eqn2)$

Divide equation 2 by equation 1

$\frac{2=ab}{\frac{2}{5}=ab^2}$

On simplifying we get

$5= \frac{1}{b}$

$b=\frac{1}{5}$

So the multiplicative rate of change of the function is

$a) \frac{1}{5}$

8 0

3 years ago

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Suppose that 20% of the residents in a certain state support an increase in the property tax. An opinion poll will randomly samp

aleksklad [387]

Answer:

95.44% probability the resulting sample proportion is within .04 of the true proportion.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For the sampling distribution of the sample proportion in sample of size n, the mean is $\mu = p$ and the standard deviation is $s = \sqrt{\frac{p(1-p)}{n}}$

In this question:

$p = 0.2, n = 400$

$\mu = 0.2, s = \sqrt{\frac{0.2*0.8}{400}} = 0.02$

How likely is the resulting sample proportion to be within .04 of the true proportion (i.e., between .16 and .24)?

This is the pvalue of Z when X = 0.24 subtracted by the pvalue of Z when X = 0.16.

X = 0.24

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.24 - 0.2}{0.02}$

$Z = 2$

$Z = 2$ has a pvalue of 0.9772.

X = 0.16

$Z = \frac{X - \mu}{s}$

$Z = \frac{0.16 - 0.2}{0.02}$

$Z = -2$

$Z = -2$ has a pvalue of 0.0228.

0.9772 - 0.0228 = 0.9544

95.44% probability the resulting sample proportion is within .04 of the true proportion.

6 0

3 years ago

Read 2 more answers

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago