That's impossible to say. The radius of a square is meaningless.
Answer:
Yes
Step-by-step explanation:
Good luck
Answer:
Step-by-step explanation:
function: all the points
note: x intercept is the domain, y intercept is the range
domain must paired with exact range
the domain can be more than 1, but range must be 1.
domain : 3, 5, 0 , -1, -3, -5
range: 1, 3, 4 , -3(there is 2 but we write it one) , -4
and done!
thank you!
<em><u>Answer:</u></em>
4 or 7 (Check the explanation to see which one your equation <em>actually</em> is.
<em><u>Step-by-step explanation:</u></em>
One thing I want to clarify for you, It's Evaluate, not Avaluate.
Okay so, we want to find the value of 2^3x-1 and we know x = 1.
You didn't really clarify if the expression was 
or 
, so I'll be doing both:
For , we should plug in x to get 
and then simplify to get 
.
2 to the power of 2 or is equal to 2 * 2 or 4.
The second one, , we should plug in x to get 
and then to become 
. 2 to the power of 3 or 
is 8 and then minus 1 is 7.
The answer is B.
(the equation to solve this with is: a^2 + b^2 = c^2)
