Let the 1st number be x; 2nd number be y; 3rd number be z.
x + y + z = 79
x = number we are looking for.
y = x * 5 ==> 5 times the first
z = x + 16 ==> 16 more than the first
Therefor,
x + (x * 5) + (x+16) = 79
1st step, multiply the 2nd number: x * 5 = 5x
x + 5x + x + 16 = 79
Add all like numbers:
7x + 16 = 79
To get x, transfer 16 to the other side and change its sign from positive to negative.
7x = 79 - 16
7x = 63
To get x, divide both sides by 7
7x/7 = 63/7
x = 9
To check. Substitute x by 9.
x + (x * 5) + (x+16) = 79
9 + (9 * 5) + (9 + 16) = 79
9 + 45 + 25 = 79
79 = 79 equal. value of x is correct.
0.93 = 0.9
0.18 = 0.2
0.9 + 0.2 = 1.1
Answer 1.1
Answer:
1.) the answer is the fourth one, 1/5^7
2.) the answer is the fourth one, 1/5^6
3.) the answer is the fourth one, (2^6)^-5
4.) this is seems to be a duplicate of the first one
Step-by-step explanation:
1.) by 'adding' 4 exponent values on the top it simplifies the top to simply one and 5^7 on the bottom
2.) since this is an exponent of an exponent multiply them, getting 5^-6, then simplify negative exponents.
3.) exponents of exponents are multiplied
Answer:
coordinates of the other endpoint (14; -6)
