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igomit [66]
4 years ago
13

Help :::))) ;) asapppppp :)

Mathematics
1 answer:
stealth61 [152]4 years ago
8 0
Multiply 3 with 7.
3 * 7 = 21
The value of the gift card changed by -$21 dollars.
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Simplify the problem
Natasha2012 [34]
\frac{6}{10x^2} \div  \frac{6}{10x^3-60x^2}  = \frac{6}{10x^2} \cdot  \frac{10x^3-60x^2}{6}  =\frac{1}{10x^2} \cdot  \frac{10x^2(x-6)}{1}  =x-6
5 0
3 years ago
A other one it’s easy
Sever21 [200]

midpoint = ((x1+x2)/2 , (y1+y2)/2)

 (   (3+-6)/2, (5+-6)/2)

(-3/2, -1/2)

(-1.5, -.5)

B

5 0
4 years ago
Read 2 more answers
Can anyone please help me solve for x? Thank you!
Amiraneli [1.4K]
X= (k+c):(m- ny/b)=(k+c): (mb-ny)/b= (k+c)*b/(mb-ny)
x= (bc+bk)/bm-ny

D is correct
5 0
3 years ago
Read 2 more answers
What is 242 - 198 subtract​
kirza4 [7]
The answer would be 44
7 0
3 years ago
One cell phone company charges a $76 sign-up fee and $40 per month. Another cell phone company charges $136 sign-up fee and $20
WARRIOR [948]

Answer:

The cost would be same after 3 months.

Step-by-step explanation:

Given that:

Charges of first company;

Sign up fee = $76

Per month charges = $40

Let,

x be the number of months

y be the total cost.

y = 40x + 76      Eqn 1

Charges of second company;

Sign up fee = $136

Per month charges = $20

y = 20x + 136     Eqn 2

For same cost,

Eqn 1 = Eqn 2

40x + 76 = 20x + 136

40x-20x = 136 - 76

20x = 60

Dividing both sides by 20

\frac{20x}{20}=\frac{60}{20}\\x=3

Hence,

The cost would be same after 3 months.

3 0
3 years ago
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