17) f(x) = 16/(13-x).
In order to find domain, we need to set denominator expression equal to 0 and solve for x.
And that would be excluded value of domain.
13-x =0
Adding x on both sides, we get
13-x +x = x.
13=x.
Therefore, domain is All real numbers except 13.
18).f(x) = (x-4)(x+9)/(x^2-1).
In order to find the vertical asymptote, set denominator equal to 0 and solve for x.
x^2 -1 = 0
x^2 -1^2 = 0.
Factoring out
(x-1)(x+1) =0.
x-1=0 and x+1 =0.
x=1 and x=-1.
Therefore, Vertical asymptote would be
x=1 and x=-1
19) f(x) = (7x^2-3x-9)/(2x^2-4x+5)
We have degrees of numberator and denominator are same.
Therefore, Horizontal asymptote is the fraction of leading coefficents.
That is 7/2.
20) f(x)=(x^2+3x-2)/(x-2).
The degree of numerator is 2 and degree of denominator is 1.
2>1.
Degree of numerator > degree of denominator .
Therefore, there would no any Horizontal asymptote.
10 1/2 I am pretty sure its right
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Answer:
a) Vertex is at (-3, -1)
b) y-intercept is at (0,8)
c) x intercept is at (-4,0) and (-2,0)
d) x=-3
Step-by-step explanation:
We know the vertex is the lowest or highest part of a parabola meaning all the points are reflected across. It is the only y value without a matching pair
E.x. -1 and 1, -3 and 3
The only point without a corresponding y value is (-3,-1) therefore the vertex is at (-3,-1)
The y-intercept is where the parabola meets the y axis or the x value is equal to 0, we just have to find when x = 0 to find the y intercept
y intercept: (0,8)
For the x intercept's it is just the reverse, you need to find where the parabola crosses the x axis or when y = 0
x intercept 1:(-4,0)
x intercept 2: (-2,0)
The axis of symmetry is also the x coordinate of the vertex which is 3 so
x = 3
