Answer:
all work is pictured and shown
B. RSP and PST I’m pretty sure.
Let T = the distance, in miles, a tire lasts
T ~ N(70000,4400<span>²</span>)
P(T

75000)
= P(Z

)
= P(Z

)
≈ P(Z

1.14)
= 1 - P(Z < 1.14)
≈ 1 - 0.8729
= 0.1271
<u>Answer:</u>
The solution set of given equations -x-y-z = -8 and - 4x + 4y + 5z = 7 and 2x + 2z = 4 is (3, 6, -1)
<u>Solution:</u>
Given, set linear equations are
-x – y – z = -8 ⇒ x + y + z = 8 → (1)
-4x + 4y + 5z = 7 ⇒ 4x – 4y – 5z = -7 → (2)
2x + 2z = 4 ⇒ x + z = 2 → (3)
We have to solve the above given equations using substitution method.
Now take (3), x + z = 2 ⇒ x = 2 – z
So substitute x value in (1)
(1) ⇒ (2 – z) + y + z = 8 ⇒ 2 + y + z – z = 8 ⇒ y + 0 = 8 – 2 ⇒ y = 6.
Now substitute x and y values in (2)
(2) ⇒ 4(2 – z) – 4(6) – 5z = - 7 ⇒ 8 – 4z – 24 – 5z = -7 ⇒ -9z – 16 = -7 ⇒ 9z = 7 – 16 ⇒ 9z = -9 ⇒ z = -1
Now substitute z value in (3)
(3) ⇒ x – 1 = 2 ⇒ x = 2 + 1 ⇒ x = 3
Hence, the solution set of given equations is (3, 6, -1).
Answer:
The probability that the animal chosen is brown-haired is 0.6333.
Step-by-step explanation:
Denote the events as follows:
<em>A</em> : a brown-haired rodent
<em>B</em> : Litter 1
The information provided is:

The probability of selecting any of the two litters is equal, i.e.

According to the law of total probability:

Compute the total probability of event <em>A</em> as follows:

![=[\frac{2}{3}\times\frac{1}{2}]+[\frac{3}{5}\times\frac{1}{2}]\\\\=\frac{1}{3}+\frac{3}{10}\\\\=\frac{10+9}{30}\\\\=\frac{19}{30}\\\\=0.6333](https://tex.z-dn.net/?f=%3D%5B%5Cfrac%7B2%7D%7B3%7D%5Ctimes%5Cfrac%7B1%7D%7B2%7D%5D%2B%5B%5Cfrac%7B3%7D%7B5%7D%5Ctimes%5Cfrac%7B1%7D%7B2%7D%5D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B3%7D%2B%5Cfrac%7B3%7D%7B10%7D%5C%5C%5C%5C%3D%5Cfrac%7B10%2B9%7D%7B30%7D%5C%5C%5C%5C%3D%5Cfrac%7B19%7D%7B30%7D%5C%5C%5C%5C%3D0.6333)
Thus, the probability that the animal chosen is brown-haired is 0.6333.