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Aleksandr-060686 [28]
3 years ago
13

The diagram shows a circle inside a square.

Mathematics
1 answer:
leonid [27]3 years ago
3 0

The question is incomplete (as there's no attachment to support the question).

However, I'll base my calculations base on the attached diagram to this solution.

Answer:

Shaded Area = 7.722 cm²

Step-by-step explanation:

Given.

Side of the square = 6cm

π = 3.142

Required:

Area of shaded region

First, the area of the square needs to be calculated.

Area of a square = Length * Length

Area = 6cm * 6cm

Area = 36cm²

Then we calculate the area of the circle.

To calculate this, we need to get the radius of the circle.

If the length of the sides of the square is 6 cm, then the diameter of the square is also 6 cm.

Now that we have the diameter, the radius can be calculated.

Radius, R = ½D (where R and D represent radius and diameter, respectively)

So,

R = ½ * 6 cm

R = 3cm

Area of a circle = πr²

Area = 3.142 * 3²

Are = 3.142 * 9

Area = 28.278 cm²

The shaded area is then calculated by subtracting the area of the circle from the area of the square.

Shaded Area = Area of Square - Area of Circle

Shaded Area = 36cm² - 28.278cm²

Shaded Area = 7.722cm²

Hence, the shaded area 7.722 cm²

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Isolate x in 2nd equation...

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A.4<br> -3<br> B. 3<br> - 4<br> C. 3<br> 4<br> D. 4<br> 3
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The answer should be A
8 0
4 years ago
.
Furkat [3]

Answer:

D) 2, 4, 8, 16, 32

Step-by-step explanation:

We have given four sets of sequence.

And we have to find out which sequence is not an arithmetic sequence.

For this the given sequences should satisfy the value of common difference(d) and Arithmetic Progression formula.

A.P. Formula,

T_n=a+(n-1)d

Where T_n = nth term of an A.P.

a = first term of an A.P.

n = number of terms.

d = common difference.

'd' is calculated by subtracting fist term from second term.

d = second\ term-first\ term

A) 4, 7, 10, 13, 16

d = 7-4=3

d = 10-7=3

Here d=3 and 5th term is 16.

So we find out the 5th term by using the formula of A.P. To check whether the sequence is in A.P. or not.

T_5=4+(5-1)3=4+4\times\ 3=4+12=16

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

B) 1, 2, 3, 4, 5

d =2-1=1

d =3-2=1

Here d=1 and 5th term is 5.

T_5=1+(5-1)1=1+4=5

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

C) 15, 9, 3, -3, -9

d =9-15=-6

d =3-9=-6

Here d=-6 and 5th term is -9.

T_5=15+(5-1)-6=15+4\times -6=15+(-24)=-9

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

D) 2, 4, 8, 16, 32

d_1=4-2=2

d_2=8-4=4

Here d_1=2\ But\ d_2=4

The common difference between the terms is not same.

In case of d_1.

T_5=2+(5-1)2=2+4\times 2=2+8=10

In case of d_2.

T_5=2+(5-1)4=2+4\times 4=2+16=18

Here the given sequence does not fulfills the condition of being in A.P.

Hence the given sequence is not an arithmetic sequence.

Hence the correct option is D) 2, 4, 8, 16, 32.

4 0
4 years ago
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