The mass of the solute required is 250.25 g.
<h3>What is the mass of the solute?</h3>
We know that the number of moles of the solute can be used to obtain the mass of the solute that is required. We can now try to find the mass of the solute that is required.
Concentration of the solution = 0.350M
Volume of the solution = 6.5 L
Number of moles of the solute = 0.350M * 6.5 L
= 2.275 moles
We now have the mass of the solute as;
2.275 moles * 110 g/mol
= 250.25 g
Th measured mass of the solute that we would have to use is 250.25 g.
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Missing parts;
A chemist wants to make 6.5 L of a .350M CaCl2 solution. What mass of CaCl2(in g) should the chemist use?
We have 25cm^3 of 0.1mol AgNO3.
25cm^3 = 0.025L, so we have 0.025 x 0.1 = 0.0025mol AgNO3, so
0.0025AgNO3 + 0.0025NaCl = 0.0025AgCl + 0.0025NaNO3
Change in Free Energy: ΔG(20C) = -0.064kJ (negative, so the reaction runs)
Change in Enthalpy: ΔH(20C) = -0.110kJ (negative, so the reaction is exothermic)
This reaction produces 0.358g of AgCl and 0.213g of NaNO3
Les Mclean PhD
Answer: Bromine is Actually a Halogen!
Explanation: Bromine is in the 7th column of the Periodic Table. It needs that magic 8 valence electrons and it has 7.
Hoped that helped!
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