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irina [24]
3 years ago
11

Consider these scenarios. Scenario A: Carmen reads an article in Tasty Food magazine stating that eating an apple can help you f

eel awake and alert. Scenario B: Yuki reads an article in the Professional Journal of Medicine stating that ginger root can help prevent some types of cancer. Which article is more likely to have been peer reviewed? How do you know?
Chemistry
2 answers:
Reika [66]3 years ago
5 0

Answer:

Scenario B

Explanation:

In Scenario B; Yuki reads an article in the Professional Journal of Medicine stating that ginger root can help prevent some types of cancer. The article was published in a professional journal. Manuscripts sent to professional journals for publication must pass through a peer review process in order to ascertain the reliability of the data presented.

Magazine articles may not go through a peer review process since it is not written for the consumption of a professional audience.

Harman [31]3 years ago
5 0

Answer:

Sample Response: The article that Yuki read (Scenario B) has been peer reviewed. This article is published in a scientific journal and has been judged for quality by other professionals in the field.

Explanation:

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We might think of a porous material as being a composite wherein one of the phases is a pore phase. Estimate upper and lower lim
eduard

Answer:

The upper and lower limits for the room-temperature thermal conductivity of a magnesium oxide material having a volume fraction of 0.10 of pores that are filled with still air are

Ku = 38.252 W/mK

K lower = 0.199 W/mK

Explanation:

As we know  

Ku = Vp * Kair + Vmagnesium * K metal  

Ku = 0.10 *0.02 + (1-0.25) * 51

Ku = 38.252 W/mK

The lower limit  

K lower = Kmetal* Kair/( Vp * Kmetal + Vmetal * K air)

K lower = (0.02*51)/(0.10*51 + 0.90 * 0.02)

K lower = 0.199 W/mK

8 0
3 years ago
Although chemical digestion occurs throughout the digestive system, it mostly occurs in the: Aesophagus and stomach B) liver and
frez [133]

Answer:

The digestive role of the liver is to produce bile and export it to the duodenum. The gallbladder primarily stores, concentrates, and releases bile. The pancreas produces pancreatic juice, which contains digestive enzymes and bicarbonate ions, and delivers it to the duodenum.

Explanation:

The chemical process of digestion begins during chewing as food mixes with ... The esophagus is a tubular organ that connects the mouth to the stomach. ... Acid reflux or “heartburn” occurs when the acidic digestive juices escape into the esophagus. ... The secretions of the liver, pancreas, and gallbladder are regulated by ...

-Both our right just choose one,

6 0
3 years ago
Explain the reaction between metallic hydroxides and a dilute acid?
dolphi86 [110]
The hydroxide (OH) in the metallic hydroxide will react with the hydrogen in an acid to form H2O. The remaining ions will combine to form a salt. Therefore a metal hydroxide and an acid will form a salt + water.
7 0
3 years ago
Which term best describes the type of bonding in magnesium chloride
max2010maxim [7]
Ionic would be the answer
5 0
3 years ago
CO2(g)+CCl4(g)⇌2COCl2(g) Calculate ΔG for this reaction at 25 ∘C under these conditions: PCO2PCCl4PCOCl2===0.140 atm0.185 atm0.7
padilas [110]

<u>Answer:</u> The \Delta G for the reaction is 54.425 kJ/mol

<u>Explanation:</u>

For the given balanced chemical equation:

CO_2(g)+CCl_4(g)\rightleftharpoons 2COCl_2(g)

We are given:

\Delta G^o_f_{CO_2}=-394.4kJ/mol\\\Delta G^o_f_{CCl_4}=-62.3kJ/mol\\\Delta G^o_f_{COCl_2}=-204.9kJ/mol

To calculate \Delta G^o_{rxn} for the reaction, we use the equation:

\Delta G^o_{rxn}=\sum [n\times \Delta G_f(product)]-\sum [n\times \Delta G_f(reactant)]

For the given equation:

\Delta G^o_{rxn}=[(2\times \Delta G^o_f_{(COCl_2)})]-[(1\times \Delta G^o_f_{(CO_2)})+(1\times \Delta G^o_f_{(CCl_4)})]

Putting values in above equation, we get:

\Delta G^o_{rxn}=[(2\times (-204.9))-((1\times (-394.4))+(1\times (-62.3)))]\\\Delta G^o_{rxn}=46.9kJ=46900J

Conversion factor used = 1 kJ = 1000 J

The expression of K_p for the given reaction:

K_p=\frac{(p_{COCl_2})^2}{p_{CO_2}\times p_{CCl_4}}

We are given:

p_{COCl_2}=0.735atm\\p_{CO_2}=0.140atm\\p_{CCl_4}=0.185atm

Putting values in above equation, we get:

K_p=\frac{(0.735)^2}{0.410\times 0.185}\\\\K_p=20.85

To calculate the gibbs free energy of the reaction, we use the equation:

\Delta G=\Delta G^o+RT\ln K_p

where,

\Delta G = Gibbs' free energy of the reaction = ?

\Delta G^o = Standard gibbs' free energy change of the reaction = 46900 J

R = Gas constant = 8.314J/K mol

T = Temperature = 25^oC=[25+273]K=298K

K_p = equilibrium constant in terms of partial pressure = 20.85

Putting values in above equation, we get:

\Delta G=46900J+(8.314J/K.mol\times 298K\times \ln(20.85))\\\\\Delta G=54425.26J/mol=54.425kJ/mol

Hence, the \Delta G for the reaction is 54.425 kJ/mol

7 0
3 years ago
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