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Furkat [3]
3 years ago
7

An airplane is flying at 35000 feet above sea level. The airplane starts to descend at a rate of 2500 feet per minute. Let m be

the number of minutes. Which of the following expression describe the height of the airplane after any given number of minutes?
Mathematics
1 answer:
Flura [38]3 years ago
8 0
Answer:

In this case, the airplane is flying at 35000 feet and descend 2500 feet every minute. That means the airplane descend rate is 2500 feet/min. Since the duration is m minute then you need to multiply it by the descending rate. Then the formula that can count the airplane height would be:

Airplane height:
35000feet - (2500feet/min x m min)
35000feet - 2500m feet
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Answer:

Each point reflected across the x-axis, goes from (x, y) --> (x, -y), which means that we keep the x coordinate the same, but multiply the y coordinate by -1:

L (-2, 4) --> (-2, -4)

M (2, 1) --> (2, -1)

N (-4, -3) --> (-4, 3)

Step-by-step explanation:

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2 years ago
How do we figure this out
lisov135 [29]

Answer:

Pair 1: 10 cm and 2 cm. and the sum is 12 cm.

Pair 2: 20 cm and 4 cm. and the sum is 24 cm.

Step-by-step explanation:

Area of a rectangle is given by A = LW, where L is the length and W is the width of the rectangle.

Pair 1:

For the first rectangle W = 4 cm and A = 40 sq, cm

Then L = \frac{A}{W} = \frac{40}{4} = 10 cm.

For the second rectangle W = 4 cm and A = 8 sq, cm

Then L = \frac{A}{W} = \frac{8}{4} = 2 cm.

Therefore, the sum of two unknown lengths = 10 + 2 = 12 cm. (Answer)

Pair 2:

For the first rectangle W = 4 cm and A = 80 sq, cm

Then L = \frac{A}{W} = \frac{80}{4} = 20 cm.

For the second rectangle W = 4 cm and A = 16 sq, cm

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2 years ago
1. Solve for y in the figure below.<br> X<br> 6<br> 8<br> 8
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IRINA_888 [86]

Answer:

  (a)  (6, 2)

Step-by-step explanation:

The system of equations has one of them in y= form, so it lends itself to solution by substitution.

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Using the equation for y to substitute into the first equation, we have ...

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  2x +1/2x -5 = 10 . . . . . eliminate parentheses

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Using the equation for y, we have ...

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2 years ago
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