Answer:
56
Step-by-step explanation:
7((9+4)-(12-7))
7(13-5)
7×8
1.5km = 1500m
To find the percentage take 15 and divide it by 1500, then times by 100
15/1500 x 100 = 1%
Answer:
The rate is the distance divided by the time.
60 feet in 10 seconds = 60 ft / 10 sec = 6 ft / sec
42 feet in 6 seconds = 42 ft / 6 sec = 7 ft / sec <--- We have a winner!
Step-by-step explanation:
Answer:
x=12
Step-by-step explanation:
Simplifying
30 + 4x + 2 = 8 + 6x
Reorder the terms:
30 + 2 + 4x = 8 + 6x
Combine like terms: 30 + 2 = 32
32 + 4x = 8 + 6x
Solving
32 + 4x = 8 + 6x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-6x' to each side of the equation.
32 + 4x + -6x = 8 + 6x + -6x
Combine like terms: 4x + -6x = -2x
32 + -2x = 8 + 6x + -6x
Combine like terms: 6x + -6x = 0
32 + -2x = 8 + 0
32 + -2x = 8
Add '-32' to each side of the equation.
32 + -32 + -2x = 8 + -32
Combine like terms: 32 + -32 = 0
0 + -2x = 8 + -32
-2x = 8 + -32
Combine like terms: 8 + -32 = -24
-2x = -24
Divide each side by '-2'.
x = 12
Simplifying
x = 12
Answer:
A) 34.13%
B) 15.87%
C) 95.44%
D) 97.72%
E) 49.87%
F) 0.13%
Step-by-step explanation:
To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:
P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)
= 0.5 - 0.1587 = 0.3413
It means that the PERCENT of scores that are between 90 and 100 is 34.13%
At the same way, we can calculated the percentages of B, C, D, E and F as:
B) Over 110

C) Between 80 and 120

D) less than 80

E) Between 70 and 100

F) More than 130
