<u>Answer:</u> The partial pressure of hydrogen is 93.9 kPa.
<u>Explanation:</u>
To calculate the partial pressure of hydrogen, we will follow Dalton's Law.
This law states that the total pressure of a mixture of gases is equal to the sum of the individual pressures exerted by the constituent gases.
Mathematically,
According to the question,
We are given:
Putting values in above equation, we get:
Hence, the partial pressure of hydrogen is 93.9 kPa.
Answer:
There arr 1.5*1024 molecules in 2.40 moles of H2O.
Answer:7,070.74
Explanation:because frequency has a lot of energy
First we find for the wavelength of the photon released due
to change in energy level. We use the Rydberg equation:
1/ʎ = R [1/n1^2 – 1/n2^2]
where,
ʎ is the wavelength
R is the rydbergs constant = 1.097×10^7 m^-1
n1 is the 1st energy level = 1
n2 is the higher energy level = infinity, so 1/n2 = 0
Calculating for ʎ:
1/ʎ = 1.097×10^7 m^-1 * [1/1^2 – 0]
ʎ = 9.1158 x 10^-8 m
Then calculate the energy using Plancks equation:
E = hc/ʎ
where,
h is plancks constant = 6.626×10^−34 J s
c is speed of light = 3x10^8 m/s
E = (6.626×10^−34 J s * 3x10^8 m/s) / 9.1158 x 10^-8 m
E = 2.18 x 10^-18 J = 2.18 x 10^-21 kJ
This is still per atom, so multiply by Avogadros number =
6.022 x 10^23 atoms / mol:
E = (2.18 x 10^-21 kJ / atom) * (6.022 x 10^23 atoms /
mol)
E = 1312 kJ/mol
5678+910=13000
257-466=198
