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Snowcat [4.5K]
3 years ago
9

N2(g) + 3h2(g) ⇌ 2nh3(g) the equilibrium constant kc at 375°c is 1.2. starting with [h2]0 = 0.76 m, [n2]0 = 0.60 m and [nh3]0 =

0.48 m, which concentration(s), if any, will have increased when the mixture comes to equilibrium?
Chemistry
1 answer:
nekit [7.7K]3 years ago
8 0
N2(g)   +  3  H2(g) =  2NH3(g)

Qc =  (NH3^2)   / { (N2)(H)^3)}

Qc=  0.48^2  /{ ( 0.60) (0.760^3) }=  0.875

Qc < Kc  therefore  the  equilibrium  will   shift     to  the  right.  This  implies  that  Nh3  concentration  will    increase    
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Answer:

0.25 mol/L

Explanation:

The following data were obtained from the question:

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Applying the dilution formula, we can easily find the concentration of the diluted solution as follow:

C1V1 = C2V2

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C2 = (0.5 x 4 )/ 8

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Converting °F into °C;

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Converting K into °C;

                                   °C  =  K - 273

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