Answer:
Explanation:
The five steps used for solving design problems are:
1. Define the problem
2. Gather pertinent information
3. Generate multiple solutions
4. Analyze and select a solution
5. Test and implement the solution
1. The first step of engineering design is to identify the problem.
2. The inputs to this activity include the research the problem, perhaps supplemented with evaluate possible solutions, both produced during product design.
3. In terms of the software life cycle, engineering design occurs during the protype creation and selection phase.
4. A good way to engage the problem during this activity is to test and evaluate the protype, which produces the main outputs of this activity.
The banking angle of curved road to allow to move without slipping is 11.53 ⁰.
<h3>
Banking angle of curved road</h3>
The banking angle of curved road is calculated as follows;
V(max) = √(rg tanθ)
where;
- r is radius of the curve
- g is acceleration due to gravity
V² = rg tanθ
tanθ = V²/rg
tanθ = (61²)/(1860 x 9.8)
tanθ = 0.204
θ = arc tan(0.204)
θ = 11.53 ⁰
Thus, the banking angle of curved road to allow to move without slipping is 11.53 ⁰.
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The Cat’s Gravity To The Ground And The Action Of The Cat’s Paws Pushing Back Off Of The Ground Springing It Forward.
Answer:
5.625km/h
Explanation:
We are given that
Distance between home and market, d=2.5 km
Speed, v1=5km/h
Speed, v2=7.5 km/h
We have to find the average speed of the man over the interval of time 0 to 40min.
Time,
Using the formula
1 hour =60 min
Distance traveled by man in 10 min with speed 7.5 km/h=
Therefore,
Total distance covered=2.5+2.5/2=3.75 km
Time=40 min=40/60=2/3 hour
Average speed=
Average speed=
Answer:
The correct answer is:
a) remain where it is released
Explanation:
The concept of density seeks to measure the weight of an object in relation to its size. It is the measure of how packed together the particles of that object are. An object placed in a liquid displaces a certain volume of the liquid, based on the relative density of the object and the liquid.
If an object is less dense than a liquid in which it is placed, it displaces a smaller volume of the liquid than its volume, hence only some part of the object will be seen to be under the liquid, the other part will float.
If an object is denser than the liquid in which it is placed, it displaces a larger volume of the liquid than its own volume, making the object to sink and is submerged, sometimes to the bottom of the liquid, but mostly below the point at which it was released.
Finally, if the density of an object and the liquid into which it is submerged is the same. the object's mass per unit volume is the same as the liquid's mass per unit volume, hence the weight and force created due to density will balance and cancel each other out hence making the object to remain where it was submerged.