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3 years ago

Describe the three particles that make up an atom (name, charge, and location in the atom).

2 answers:

5 0

Answer:Protons, neutrons, and electrons are the three main subatomic particles found in an atom. Protons have a positive (+) charge. An easy way to remember this is to remember that both proton and positive start with the letter "P." Neutrons have no electrical charge.

vaieri [72.5K]3 years ago

3 0

Proton is positive
Neutron is neutral
Electron is negative

The nucleus is made of protons and neutrons while the electrons surround the nucleus in the form of probability “clouds”

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PLease HURRY ITS REALLY EASY.

Leya [2.2K]

[Reflection]

- This occurs when light bounces off a surface (reflection is when light bounces off of something, a medium, but doesn't go through.)

- Best with a smooth surface (it is easiest for light to bounce off when the surface is smooth)

- If not for this behavior, mirrors wouldn't work (mirrors use reflection, if they did not you would not be able to see your reflection)

[Refraction]

- Light moves from one medium to another (when light moves from one medium to another, it refracts)

- Lenses in your glasses to bend light waves (refraction is all about bending light waves, so this option falls under this category)

- Microscopes and telescopes take advantage of this behavior of light (again, refraction is bending light waves. When you bend a light wave, it can make it easier to see [larger, smaller, etc] so this option is refraction)

- Light wave changes speed (light does not change speed when being reflected because it is in the same medium and just bouncing, but it refraction is changes mediums so it will bend and change speed)

[Note]

- Some of these can be figured out by knowing the definitions. For example, refraction is defined as "change in direction ... of any wave as a result of its traveling at different speeds at different points along the wave front" (Oxf/ord Languages)

Have a nice day!

I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

3 0

3 years ago

A 7.3 kg bowling ball would require how much force if you use a broom to

il63 [147K]

Answer:

0.219N

Explanation:

Given data

mass= 7.3kg

acceleration= 0.03m/s^2

We know that

F=ma

substitute

F= 7.3*0.03

F= 0.219N

Hence the applied force is 0.219N

7 0

3 years ago

Suppose the initial position of an object is zero, the starting velocity is 3 m/s and the final velocity was 10 m/s. The object

forsale [732]

The area of the rectangle plus the area of the triangle under the line .-.

4 0

4 years ago

Read 2 more answers

An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.300 rev/s . The magnitude

Salsk061 [2.6K]

1) 1.2 m/s

First of all, we need to find the angular velocity of the blade at time t = 0.200 s. This is given by

$\omega_f = \omega_i + \alpha t$

where

$\omega_i = 0.300 rev/s$ is the initial angular velocity

$\alpha = 0.895 rev/s^2$ is the angular acceleration

Substituting t = 0.200 s, we find

$\omega_f = 0.300 + (0.895)(0.200)=0.479 rev/s$

Let's now convert it into rad/s:

$\omega_f = 2\pi \cdot 0.479 rev/s=3.01 rad/s$

The distance of a point on the tip of the blade is equal to the radius of the blade, so half the diameter:

$r=\frac{0.800}{2}=0.400 m$

And so now we can find the tangential speed at t = 0.200 s:

$v=\omega_f r =(3.01)(0.400)=1.2 m/s$

2) $2.25 m/s^2$

The tangential acceleration of a point rotating at a distance r from the centre of the circle is

$a_t = \alpha r$

where $\alpha$ is the angular acceleration.

First of all, we need to convert the angular acceleration into rad/s^2:

$\alpha = 0.895 rev/s^ \cdot 2 \pi =5.62 rad/s^2$

A point on the tip of the blade has a distance of

r = 0.400 m

From the centre; so, the tangential acceleration is

$a_t = (5.62)(0.400)=2.25 m/s^2$

3) $3.6 m/s^2$

The centripetal acceleration is given by

$a=\frac{v^2}{r}$

where

v is the tangential speed

r is the distance from the centre of the circle

We already calculate the tangential speed at point a):

v = 1.2 m/s

while the distance of a point at the end of the blade from the centre is

r = 0.400 m

Therefore, the centripetal acceleration is

$a=\frac{1.2^2}{0.400}=3.6 m/s^2$

7 0

3 years ago

. Reem took a wire of length 10 cm. Her friend Nain took a wire of 5 cm of the same material and thickness both of them connecte

Umnica [9.8K]

Given :

Reem took a wire of length 10 cm. Her friend Nain took a wire of 5 cm of the same material and thickness both of them connected with wires as shown in the circuit given in figure. The current flowing in both the circuits is the same.

To Find :

Will the heat produced in both the cases be equal.

Solution :

Heat released is given by :

H = i²Rt

Here, R is resistance and is given by :

$R = \dfrac{\rho L}{A}$

So,

$H = i^2\times \dfrac{\rho L}{A} t\\\\H = \dfrac{i^2\rho Lt}{A}$

Now, in the question every thing is constant except for the length of the wire and from above equation heat is directly proportional to the length of the wire.

So, heat produced by Reem's wire is more than Nain one.

Hence, this is the required solution.

7 0

3 years ago