Answer:
A) 2.89 × 105 N/C, radially inward
Explanation:
The magnitude of the electric field generated by a charged sphere is given by the following formula:
( 1 )
k: Coulomb's constant = 8.98*10^9 Nm^2/C^2
Q: charge of the sphere = -6.50*10^-6 C
r: distance from the center of the sphere to the point in which E is calculated
r = 0.150m + 0.300m = 0.450 m
You replace the values of Q and r in the equation (1):
The electric field points radially inward because the charge is negative.
hence, the answer is:
A) 2.89 × 105 N/C, radially inward
As wavelength increase, frequency decrease
<span>The terminal velocity of a sand grain in the air is greater than the terminal velocity of the same sand grain in seawater. The terminal velocity is greater in the air because it is less dense compared to a much denser sea water. Terminal velocity takes lace when an object is constantly free-falling.</span>
Answer:
Va = 5000 m / 3600 s = 1.39 m/s
(Va - Vb) 60 = 10
Vb = Va - .167 = 1.22 m/s
(Va - Vb) T = 4200 Π where T is time for A to complete 1 more lap
.17 T = 4200 Π
T = 24700 Π time for A to again catch B
N = 1.39 * 24700 Answer:
Va = 5000 m / 3600 s = 1.39 m/s
(Va - Vb) 60 = 10
Vb = Va - .167 = 1.22 m/s
(Va - Vb) T = 4200 Π where T is time for A to complete 1 more lap
.17 T = 4200 Π
T = 24700 Π time for A to again catch B
N = 1.39 * 24700 Π / (4200 Π) = 8.2 laps
A will make 8 but not 9 rounds before catching B
Answer:
0 m/s
Explanation:
Average velocity of an object is given by the net displacement divided by time taken. Displacement is equal to the shortest path covered by the object.
In this problem, a player runs the length of the 30-meter court and back. The player does this three times in 60 seconds.
As the player runs the court and returns to the original point. It would mean that the shortest path covered is 0.
Average velocity = displacement/time
v=0/30
v = 0 m/s
Hence, the correct option is (1).
