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GalinKa [24]
3 years ago
7

A particle moves in a circular path of radius 0.10 m with a constant angular speed of 5 rev/s. The acceleration of the particle

is: A. 0.10p m/s2 B. 0.50 m/s2 C. 500p m/s2 D. 1000p2 m/s2 E. 10p2 m/s2
Physics
1 answer:
Darya [45]3 years ago
7 0

Answer:

2.5 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity.

The S.I unit of acceleration is m/s²

For circular motion, the expression for acceleration is given as,

a = ω²r ................ Equation 1

Where a = acceleration of the particle, ω = angular speed of the particle, r = radius of the circular path.

Given: ω = 5 rev/s = 31.42 rad/s, r = 0.10 m.

Substitute into equation 1

a = 5²(0.10)

a = 25(0.10)

a = 2.5 m/s²

Hence the acceleration of the particle = 2.5 m/s²

Hence, none of the option  is correct

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a spherical mirror produces a magnification of -1 on a screen placed at a distance of 40cm from the mirror i) write the type of
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f =-20 cm

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