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3 years ago

8x:2+9=3x+13 What is the result of this equation? Plssss Qual é o resultado dessa equação? Pfv

Mathematics

1 answer:

olasank [31]3 years ago

5 0

Exact form : 4/13
decimal form : .0.307692

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Karla, Ruby, Anna, and Megan each had a balance of $0 in her bank account on the first day of April. Here are their account bala

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Anna had the biggest change in their bank account because they dropped by $48. The rest of the numbers are closer to zero while -48 is the furthest from zero, therefore it is the biggest change.

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3 years ago

Read 2 more answers

Solve for x given the equation x-5+7=11

Alexeev081 [22]

Answer:

Step-by-step explanation:

x-5+7=11

First think of what +7 = 11 then subtract by 5

check :)

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3 years ago

What is the area of this rectangle? 10units 20units 24units 48 units

aksik [14]

Answer:

24 units ^2

Step-by-step explanation:

The base runs from 3 to 7 so the base is 7-3 = 4 units

The height runs from 2 to 8 so the height is 8-2 = 6 units

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A = bh

= 6*4 = 24 units ^2

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1 year ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

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2 years ago

How do you translate "fifty-three plus four times c is as much as 21" in an equation

Ulleksa [173]

$53+4c=21 \\ \\ 4c=21-53 \\ \\ 4c=-32 \\ \\ c= -\frac{32}{4} \\ \\ \boxed{c=-8}$

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3 years ago