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Maksim231197 [3]
3 years ago
12

. . ’ ‘ V v : c v » L ‘ 7 . -.z > " , ’ > r - ’ » ‘ - _ _ _ V g » ,, : 3x + 3 arr ’ ’ 2x + 4

Mathematics
1 answer:
Masteriza [31]3 years ago
8 0
Parallel lines have the same slope.

'a' is the only choice that has the same slope (-5/4)
as the line in the question.
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PLEASE HELP! WILL MARK AND GIVE POINTS.
marshall27 [118]

Answer:

im not sure but i think it might be d

Step-by-step explanation:

6 0
3 years ago
Find the value of x.<br> a.17<br> b.12<br> c.40<br> d.18<br> e.none are correct
Natali5045456 [20]

Answer:

b.12

Step-by-step explanation:

<u>Key skills needed: Interior Angle Measure Theorem, Equation Creation</u>

1) First, we need to classify this shape. It has 7 sides, which means that we can use the Interior angle Theorem to find out the sum of all the interior angle measures

The theorem is:    S = (n - 2)180

S is the sum of all interior angle measures

n is the number of sides of the polygon

2) With this, we can plug in 7 for "n" (Since the figure has 7 sides) and get:

---> S = (7-2)180

---> (7-2) is 5 since 7 - 2 = 5 so --> S = 5(180)

---> 5(180) is the same as 5 x 180 which is 900 so --> S = 900

This means that the sum of all interior angles is 900 degrees.

3) Now, we have to find out the sum of all the angles that they gave us so:

---> 10x + 10x + 9 + 133 + 9x + 14 + 12x - 9 + 10x + 5 + 136 = 900

The left side is the sum of all interior angles in the shape, and the right side is what the sum should be when expressed as a number.

4) We have to combine all like terms on the left side:

---> 10x + 10x + 9x + 12x + 10x = 51x

---> 9 + 133 + 14 -9+5+136 = 288    

5) This means that ---> 51x + 288 = 900

Subtract 288 from both sides  and get:

---> 51x = 612    (900-288 = 612)

Then divide by 51 from both sides and get:

---> x = 12     (612 ÷ 51 = 12)

Therefore b.12 is your answer.

<em>Hope you understood and have a nice day!! :D</em>

8 0
3 years ago
A second-order linear differential equation for y(t) is said to be homogeneous if... every term involve either y or its derivati
swat32

Answer: Hello!

A second order differential equation has the next shape:

y''(t) + p(t)y'(t) + q(t)y(t) = g(t)

where p(t), q(t) and g(t) are functions of t, that can be constant numbers for example.

And is called homogeneus when g(t) = 0, so you have:

y''(t) + p(t)y'(t) + q(t)y(t) = 0

Then a second order differential equation is homogeneus ef every term involve either y or the derivatives of y.

4 0
3 years ago
A committee must be formed with 4 teachers and 5 students. If there are 11 teachers
Ivenika [448]

Answer:

11C4 × 11C5

\binom{11}{4}   \times  \binom{11}{5}  =  \frac{11 \times 10 \times 9 \times 8}{4 \times 3 \times 2 \times 1}   \times  \frac{11 \times 10 \times 9 \times 8 \times 7}{5 \times 4 \times 3 \times 2 \times 1}  = 330 \times 462 = 152460

7 0
2 years ago
What is [(7x^3)(y^2)]^2/7 in radical form?
GuDViN [60]
Remember
x^ \frac{m}{n} = \sqrt[n]{x^m}
and
(zy)^m=(z^m)(y^m)
and
(x^m)^n=x^(mn)

so
((7x^3)(y^2))^ \frac{2}{7} = \sqrt[7]{((7x^3)(y^2))^2}=
\sqrt[7]{((7x^3)^2(y^2)^2)}=
\sqrt[7]{((7^2x^6)(y^4))}=
\sqrt[7]{((49x^6)(y^4))}=
\sqrt[7]{49x^6y^4}
8 0
3 years ago
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