In order to determine the limiting reactant, we need to obtain the number of moles of each reactant and dividing this value with the stoichiometric coefficient of the reactant. The lowest value would pertain to the limiting reactant.
For S (32 g/mol)
number of moles of S = 5/32 = 0.15625
divide by the stoichiometric coefficient,1 = 0.15625
For H2SO4
number of moles of H2SO4 = 0.0510
divide by the stoichiometric coefficient,2 = 0.02551
Therefore the limiting reactant is H2SO4
Mass of each product when limiting reactant is fully consumed
mass of SO2 = 0.0510 mol H2SO4 * (3 mol SO2/ 2 mol H2SO4) * (64 g SO2/ 1mol SO2) = 4.896 g
mass of H2O = 0.0510 mol H2SO4 * (2 mol H2O/ 2 mol H2SO4) * (18 g H2O/ 1 mol H2O) = 0.918 g H2O
The hydrological cycle refers to the circulation of water within the earth's hydrosphere in different from I. e. the liquid, solid and the gaseous forms.
We know that there are only 3 kinds of matter.
- Liquid
- Solid
- Gas
And therefore, we know that smoke, as the fire, is not solid, we see that the molecules float everywhere, and they do what they want to do. And this would be exactly to what gas it. The molecules just do their own thing.
Your answer: Gas/Molecule
Answer:
D
Explanation:
P = Pressure
V = Volume
n = Moles
R = .08206 (because we're using liters)
T = Temperature (as K)
P(50) = (4)(.08206)(308)
P(50) = 101.09792
Divide both sides by 50
P(50)/50 = 101.09792/50
P = 2.0219584
