Answer:
5a. 13.5 moles of F₂
5b. 3.33 moles of Ar.
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
3F₂ + 2Ar —> 2ArF₃
From the balanced equation above,
3 moles of F₂ reacted with 2 moles of Ar to produce 2 moles of ArF₃.
5a. Determination of the number of mole of fluorine, F₂, needed to produce 9 moles of ArF₃.
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of ArF₃.
Therefore, Xmol of F₂ will react to produce 9 moles of ArF₃ i.e
Xmol of F₂ = (3 × 9)/2
Xmol of F₂ = 13.5 moles
Thus, 13.5 moles of F₂ is needed.
5b. Determination of the number of mole of Ar needed to react with 5 moles F₂.
From the balanced equation above,
3 moles of F₂ reacted with 2 moles of Ar.
Therefore, 5 moles of F₂ will react with = (5 × 2)/3 = 3.33 moles of Ar.
Thus, 3.33 moles of Ar was consumed.
the answer is fresh water
You didn't put a + charge on one of the Ag. It has to be on the left side
2H2O + MnO2 ==> MnO4^- + 3e + 4H^+
Ag^+ + e ==> Ag^+
Those are the two BALANCED half reactions. Multiply equation 1 by 1 and equation 2 by 3 and add them.
Answer:
1. C- Three.
2. A- Methionine
3. D- Translocation.
4. C- OH.
5. A - 5'
6. A - 3' carbon
7. A. adenine and guanine
Explanation:
1. A codon is a group of three nucleotide sequence that encodes or specifies an amino acid. This means that, during translation (second stage of gene expression), when a CODON is read, an amino acid is added to the growing peptide chain.
2. The codon that initiates the translation process is called a start codon. It has a sequence: AUG and it specifies Methionine amino acid. Hence, during translation where a tRNA binds to the mRNA codon to read it and add its corresponding amino acid, a tRNA with a complementary sequence of AUG (start codon) binds to it and carries Methionine amino acid.
3. Translocation is a process during translation whereby the mRNA-tRNA moeity moves forward in the ribosome to allow another codon to move into the vacant site for translation process to continue.
4. The sugar component of a nucelotide that makes up the nucleic acid (DNA or RNA) i.e. ribose or deoxyribose, contains an hydroxyll functional group (-OH).
5. A nucleotide consists of a pentose (five carbon) sugar, phosphate group and a nitrogenous base. The phosphate group (PO43-) is attached to the 5' carbon of the sugar molecule.
6. The free hydroxyll group (-OH) of the five carbon sugar molecule in DNA is attached to its 3' carbon.
7. Nitrogenous bases are the third component of a nucleotide, the other two being pentose sugar and phosphate group. The nitrogenous bases are four viz: Adenine, Guanine, Cytosine, and Thymine. These bases are classified into Purines and Pyrimidines based on the similarity in their structure. Adenine (A) and Guanine (G) are Purines because they possess have two carbon-nitrogen rings, as opposed to one possessed by Pyrimidines (Thymine and Cytosine).
