Need a picture for reference
Step 1: Write Imbalance Equation
CH₃CHO + O₂ → CO₂ + H₂O
Step 2: Balance Carbon Atoms:
There are 2 carbon atoms at reactant side and one at product side. So multiply CO₂ with 2 to balance them. i.e.
CH₃CHO + O₂ → 2 CO₂ + H₂O
Step 3: Balance Hydrogen Atoms:
There are 4 hydrogen atoms at reactant side and 2 Hydrogen atoms at product side. So, multiply H₂O by 2 to balance Hydrogen on both sides. i.e.
CH₃CHO + O₂ → 2 CO₂ + 2 H₂O
Step 4: Balance Oxygen Atoms:
There are 3 Oxygen atoms at reactant side and 6 Oxygen atoms at product side. In order to balance them multiply O₂ on reactant side by 2.5 (5/2). i.e
CH₃CHO + 5/2 O₂ → 2 CO₂ + 2 H₂O
Step 6: Eliminate Fraction:
Multiply overall equation by 2 to eliminate fraction. i.e.
2 CH₃CHO + 5 O₂ → 4 CO₂ + 4 H₂O
When you change the number of protons in an atom, you will change the atom from one element to a different element. Sometimes, when you add a proton to an element, the element will become radioactive. If you change the number of electrons in an atom, you will get an ion of the element.
Answer: I remember looking out of the car as we pulled up to the Frantz school.”
“I thought maybe it was Mardi Gras.”
“As we walked through the crowd, I didn’t see any faces.”
“[The school] looked bigger and nicer than my old school.”
“The crowd behind us made me think this was an important place.”
“It must be college, I thought to myself.
Explanation:
Answer:
37
Cl
17
(37 is a superscript to the left of the symbol, and 17 is a subscript to the left of the symbol)
Explanation:
1) Chlorine-37 is the chlorine isotope with mass number 37.
2) The atomic mass of chlorine is 17. All the atoms of chlorine have the same atomic number (all the atoms of an element have the same atomic number). You find this number in a periodic table.
3) The isotope representation consists of:
i) The symbol of the element (Cl in this case) at the center of the representation.
ii) The mass number (37) as a superscript to the left of the symbol. That is:
37
Cl
iii) The atomic number (17) as a subscript to the left of the symbol. That completes the representation in this form:
37
Cl
17
