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Vlad1618 [11]
3 years ago
12

EMERGENCY: PLS HELP OR I WILL FAIL I WILL MARK BRAINLIEST!!

Chemistry
2 answers:
Levart [38]3 years ago
6 0

Answer:

hope it helps

Explanation:

Dvinal [7]3 years ago
6 0

Answer:

Neutron is a neutral particle located in the nucleus of the atom

Electron cloud is the area of the atom surrounding the nucleus where electrons can be found

Electron is a negatively charged particle that orbits the nucleus of an atom

Proton is a positively  charged particle located in the nucleus of an atom

Nucleus is the central part of the atom containing protons and neutrons

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A substance with a pH of 10 is how much more basic than a substance with a pH of 2?
Kazeer [188]

Answer:

The same holds true for pH values above 7, each of which is ten times more alkaline (another way to say basic) than the next lower whole value. For example, pH 10 is ten times more alkaline than pH 9 and 100 times (10 times 10) more alkaline than pH 8.

Explanation:

7 0
3 years ago
How would one convert 36 yd to centimeters 2.54 cm = 1 in)?​
morpeh [17]

Answer:

D

Explanation:

A P E X

7 0
2 years ago
Help me please. <br> Thermal energy can come from other forms of energy. Give several examples how.
pychu [463]

a heater turns electrical energy into thermal energy

the sun turns gas into thermal energy

annd i cant think of anymore but i hope this helps you

5 0
3 years ago
A 0.4272 g sample of an element contains 2.241 x 10 ^21 atoms . what is the symbol of the element?
grin007 [14]

Answer:

Likely \rm In (indium.)

Explanation:

Number of atoms: N = 2.241 \times 10^{21}.

Dividing, N, the number of atoms by the Avogadro constant, N_A \approx 6.023 \times 10^{23} \; \rm mol^{-1}, would give the number of moles of atoms in this sample:

\begin{aligned} n &= \frac{N}{N_{A}} \\ &\approx \frac{2.241 \times 10^{21}}{6.023 \times 10^{23}\; \rm mol^{-1}} \approx 3.72 \times 10^{-3}\; \rm mol \end{aligned}.

The mass of that many atom is m = 0.4272\; \rm g. Estimate the average mass of one mole of atoms in this sample:

\begin{aligned}M &= \frac{m}{n} \\ &\approx \frac{0.4272\; \rm g}{3.72 \times 10^{-3}\; \rm mol} \approx 114.82\; \rm g \cdot mol^{-1}\end{aligned}.

The average mass of one mole of atoms of an element (114.82\; \rm g \cdot mol^{-1} in this example) is numerically equal to the average atomic mass of that element. Refer to a modern periodic table and look for the element with average atomic mass 114.82. Indium, \rm In, is the closest match.

5 0
3 years ago
A 250. cm3 sample of neon is collected at standard temperature and pressure. Assuming the volume remains constant, what would be
Olenka [21]

Answer:

The answer is 118 kPa.

Explanation:

3 0
2 years ago
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