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3 years ago

What's the difference between nahco3, khco3, na2co3, and k2co3?

1 answer:

3 0

<span>Answer: Sodium hydrogen carbonate (NaHCO3), also called sodium bicarbonate, is baking soda. It is also important in controlling the acidity of blood. Potassium bicarbonate is a colorless, odorless, slightly basic, salty substance. Sodium carbonate Na2CO3, is the water-soluble sodium salt of carbonic acid. Potassium carbonate (K2CO3) is a white salt, soluble in water (insoluble in ethanol) which forms a strongly alkaline solution.</span>

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Why are fingertips wet with saliva before counting money?

poizon [28]

Answer:

It helps to get a better grip on the money.

Explanation:

8 0

2 years ago

What is the voltage of the voltaic cell Zn|Zn2+||Cu2+|Cu at 298 K if [Zn2+] = 0.2 M and [Cu2+] = 4.0 M? Cu2+ + 2e- → Cu Eo = +0.

OLga [1]

Answer : The voltage of the voltaic cell is 1.14 V

Explanation :

From the given cell representation, we conclude that

The copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction: $Cu^{2+}+2e^-\rightarrow Cu$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

$Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

To calculate the $E^o{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=E^o_{(Cu^{2+}/Cu)}-E^o_{(Zn^{2+}/Zn)}$

Putting values in above equation, we get:

$E^o_{cell}=(+0.34V)-(-0.76V)$

$E^o_{cell}=1.1V$

Now we have to calculate the emf or voltage of the cell.

Using Nernest equation at 298 K :

$E_{cell}=E^o_{cell}-\frac{0.0592}{n}\log \frac{[Zn^{2+}]}{[Cu^{2+}]}$

where,

n = number of electrons in oxidation-reduction reaction = 2

$E_{cell}$ = ?

Now put all the given values in the above equation, we get:

$E_{cell}=1.1-\frac{0.0592}{2}\log \frac{0.2}{4.0}$

$E_{cell}=1.14V$

Therefore, the voltage of the voltaic cell is 1.14 V

5 0

3 years ago

what is the molecular formula of a compound with an empiricla formula of ch and a molecular mass of 78

Dovator [93]

Answer:

C6H6

Explanation:

We can obtain the molecular formula from the empirical formula.

What we need do here is:

(CH)n = 78

The n shows the multiples of both element present in the actual compound. It can be seen that carbon and hydrogen have the same element ratio here. We then use the atomic masses of both elements to get the value of n. The atomic mass of carbon is 12 a.m.u while the atomic mass of hydrogen is 1 a.m.u

(1 + 12)n = 78

13n = 78

n = 78/13 = 6

The molecular formula is

(CH)n = (CH)6 = C6H6

6 0

3 years ago

You have a big block of ice you chip off a small chunk which has more thermal energy?

gayaneshka [121]

I think ita c sense its the same object

3 0

3 years ago

Read 2 more answers

Kendra and Jordan gather firewood. The wood is cool to the touch, but the campfire they make warms their hands. Which statement

Free_Kalibri [48]

Answer:

Explanation:

6 0

3 years ago