I am attaching a picture cause I cannot write it directly
Hope it helps
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Molarity is defined as the number of moles of solute in 1 L of solution
number of NaOH moles present - 0.20 mol
volume of solution - 150 mL
since molarity is taken as number moles of solute in 1000 mL
if 150 mL contains - 0.20 mol
then 1000 mL should contain - 0.20 / 150 x 1000 = 1.33 mol
therefore molarity is 1.33 M
It seems like the answer is C, you really just need to use the process of elimination.
4 total bonds if u have double,or triple then subtract from 4
