<u>Answer:</u> The average atomic mass of lithium is 6.9241 u.
<u>Explanation:</u>
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:
....(1)
- <u>For
isotope:</u>
Mass of
isotope = 6 u
Percentage abundance of
isotope = 7.59 %
Fractional abundance of
isotope = 0.0759
- <u>For
isotope:</u>
Mass of
isotope = 7 u
Percentage abundance of
isotope = 92.41%
Fractional abundance of
isotope = 0.9241
Putting values in equation 1, we get:
![\text{Average atomic mass of Lithium}=[(6\times 0.0759)+(7\times 0.9241)]](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20Lithium%7D%3D%5B%286%5Ctimes%200.0759%29%2B%287%5Ctimes%200.9241%29%5D)

Hence, the average atomic mass of lithium is 6.9241 u.
Answer:
Law of cross-cutting relationships
Explanation:
This interpretation is based on the law of cross - cutting relationships.
This law states that "faults and fractures that cuts through a rock are younger than the rocks they cut through".
- In a sequence of strata, the strata that are not cut through by these features are younger than the cross -cutting features.
- The igneous intrusion is younger since it cuts through the rock layers.
Its the second one. Add the exponents and you'll get 7
Answer: -
Solubility of a substance depend on the balance of intermolecular forces between the solvent and solute, and the entropy change that accompanies this process.
Temperature and pressure also plays a role in solubility.
A solution having Group 1 cations like lithium, sodium, potassium etc are always soluble.
A solution having NH₄⁺ is soluble.
All salts with anion as nitrates, acetates, chlorates, and perchlorates are soluble in water.
Answer:
S = 21.92 %
F = 78.08 %
Explanation:
To find the percent composition of each element in SF6, we must find the molar mass of SF6 first.
Molar mass of SF6 = 32 + 19(6)
= 32 + 114
= 146g/mol
mass of Sulphur (S) in SF6 = 32g
mass of Fluorine (F) in SF6 = 114g
Percent composition = mass of element/molar mass of compound × 100
- % composition of S = 32/146 × 100 = 21.92%.
- % composition of F = 114/146 × 100 = 78.08%.