Find the polynomial. {5} is the solution set of A) x^2-5x+25=0 B)x^2+10x+25=0 C)x^2-10x+25=0 D)x^2+5x+25=0

Mathematics

2 answers:

Alecsey [184]4 years ago

7 0

Answer:

option:C

Step-by-step explanation:

A) on putting x=5 in equation $x^2-5x+25=0$ we have that the equation is not equal to 0 it gives the value 25. so {5} is not a solution set of A.

B) on putting x=5 in the equation $x^2+10x+25=0$ we have the equation is not equal to 0 it gives the value 100. so {5} is not a solution set of B.

C)on putting x=5 in the equation $x^2-10x+25=0$ , the equation gives the value 0. so {5} is a solution set of C.

D)on putting x=5 in the equation $x^2+5x+25=0$ equation does not give the value zero it gives 75. so {5} is not a solution set for D.

max2010maxim [7]4 years ago

6 0

The answer is C.) <span>x^2-10x+25=0 </span>

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An exponentially function is expressed in the form y = axb^x . The relation represents a growth when _ and a decay when _ .

Sergio [31]

Answer:

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Step-by-step explanation:

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