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Fiesta28 [93]
3 years ago
14

Blood in the heart chambers is separated from the myocardium by a thin membrane called the __________.

Biology
1 answer:
Ann [662]3 years ago
7 0
It is separated by the endocardium !
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Veronica wrote Charles Darwin’s main points on the board, but she made a mistake in one point.
Leno4ka [110]

<span>The question above is incomplete, the remaining part of the question is given below:
1. Since more offspring are produced than an environment can support, organisms within a population must compete for resources to survive.

2. Due to variations within the population, some competitors will be better equipped for survival than others.

3. The best-equipped organisms will survive and will produce well-equipped offspring. 

4. Variations that help with survival will be passed on to future generations and will rapidly change the whole population.

Which point is flawed as written above?
A. point 1
B. point 2
C. point 3
D. point 4</span>

ANSWER

The correct option is D.

All the options written above about Darwin's theory are quite correct with the exception of option D. Charles Darwin was the scientist who proposed the theory of evolution by mean of natural selection. Darwin submitted that, due to the scarcity of needed resources in an environment, it is only the fittest individuals in a particular population that will be able to survive and produce offspring that share their adaptability features. As this continue from generation to generation, it leads to evolution, which is defined as the changes overtime, which give rise to new species that share a common ancestors. Contrary to the point made in option D, evolution by natural selection is not a rapid process at all, it is a process that occur over a long period of time.

7 0
3 years ago
A teenage patient complains of frequently being tired and lethargic. The doctor notices the patient is pale and asks, "Do either
Butoxors [25]
D, specifically because if the parents have/had this, it is likely the patient does
5 0
3 years ago
Read 2 more answers
American vultures used to be classified in the same family as African vultures. Which discovery caused scientists to reclassify
Mashutka [201]

Answer:

DNA evidence revealed the American vultures share more recent ancestor with the Storks

Explanation:

The hooded vultures that is mostly found in the African continent have a close resemblance with the American vultures and were traditionally classified to belong to the Falcon family.

However, it was observed that the American vultures shared a similar behavior with Stork which is not common to the vulture found in Africa, including the hooded vulture. The Stork and the American vulture exhibit the behavior of urinating on their legs when being overheated. When the urine gets evaporated, it helps them to cool their body temperature.

This shared behavior between the storks and the American vultures led scientists into using molecular analysis in analyzing the DNA of the hooded vultures found in Africa, the American vultures, and the stork.

Evidence from the DNA analysis later revealed that the American vultures and the storks share a more common DNA sequences than African vultures and American vultures do.

5 0
3 years ago
According to the phylogenetic tree to the right A.An ancestor of Eubacteria B.Archaebacteria came from Eubacteria C.Animals gave
gregori [183]

Answer:

There is something wrong with this question.

Check and reword.

Explanation:

The Choices of answers need revision.

3 0
3 years ago
En un cruce entre peces naranjas y peces grises se obtiene una generación (f1) de 50% peces grises . Realice el cruce y explique
Ilya [14]

Answer:

Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).

Explanation:

<u>Datos disponibles:</u>

  • Cruce entre peces naranjas y peces grises
  • 50% de la F1 son peces grises
  • Naranja dominante sobre gris

Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo  para color gris <em>n</em>.

Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.

Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.

Cruce:

Parental)      Nn    x     nn

Gametas)   N    n       n    n

Fenotipos) Naranja     Gris

Cuadro de Punnett)      N           n

                            n       Nn         nn

                            n       Nn         nn

F1)  2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn

     2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,    

     nn

     50% de la progenie será color naranja (Nn)

     50% de la progenie será color gris (nn)

               

3 0
3 years ago
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