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3 years ago

What do I scan to confirm that a book is relevant and valuable as a source

1 answer:

7 0

It's genre. Look for something either on a final or starting page near the cover, and check to look if it's non fiction, or anything else that could prove it as reliable.

You might be interested in

Name each of the following chemistry structures (picture) plz

Triss [41]

Answer:

(a) 3-ethylpentane (because the longest chain is 5 carbon atoms, and ethyl is positioned at the 3rd carbon atom)

(b) 1, 2-dimethylbutane (because two methyl is positioned at the 2nd and 3rd carbon atom)

(c) 3, 4-dimethylhexane (the longest chain here is 6 carbon atoms, and two methyl is positioned at the 3rd and 4rd carbon atom)

(d) 3-methyl 4-ethylhexane ( the longest chain is 6 carbon atoms, one methyl is positioned at the 3rd carbon atom while one ethyl is positioned at the 4rd carbon atom)

(e) and (f) are similar to the question before... and I dunno how to (g) and (h) cuz I haven't learned it

Hope that you are able to answer the rest!!

4 0

4 years ago

What are the charges on ions of Group 1A, Group 3A (aluminum), and Group 5A?

arsen [322]

Answer:

Group 1A: 1+

Group 3A: 3+

Group 5A: 3+ or 5+

Explanation:

8 0

3 years ago

How do you find out how many protons,electrons, and neutrons an atom has?

Evgen [1.6K]

So the atomic number is the same as protons, and electrons and to get neutrons by subtracting number of protons from atomic mass.

8 0

3 years ago

The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C

Kay [80]

Answer: The percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

Let the fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope be 'x'. So, fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope will be '1 - x'

For $_{17}^{35}\textrm{Cl}$ isotope:

Mass of $_{17}^{35}\textrm{Cl}$ isotope = 35 amu

Fractional abundance of $_{17}^{35}\textrm{Cl}$ isotope = x

For $_{17}^{37}\textrm{Cl}$ isotope:

Mass of $_{17}^{37}\textrm{Cl}$ isotope = 37 amu

Fractional abundance of $_{17}^{37}\textrm{Cl}$ isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

$35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775$

Percentage abundance of $_{17}^{35}\textrm{Cl}$ isotope = $0.775\times 100=77.5\%$

Percentage abundance of $_{17}^{37}\textrm{Cl}$ isotope = $(1-0.775)=0.225\times 100=22.5\%$

Hence, the percentage abundance of $_{17}^{35}\textrm{Cl}$ and $_{17}^{37}\textrm{Cl}$ isotopes are 77.5% and 22.5% respectively.

6 0

3 years ago

Match each term with its correct description:

Artemon [7]

Answer:

Explanation:

Hydrocarbon:

a = An organic compound made up of only carbon and hydrogen.

Such as alkane, alkene, alkyne.

Cyclic hydrocarbon:

c = Carbon chain that form rings.

Such as benzene, cyclo heptane etc

Isomers:

d = Compounds with same molecular formula and different structural formula.

Alkanes:

e = refers to saturated hydrocarbons, no matter the shape

such as methane, ethane, propane etc.

Alkene:

f = Any hydrocarbon that have at lest one carbon carbon double bond.

such as ethene, propene, butene

Saturated hydrocarbons:

b = Carbon atoms are saturated with so many hydrogen atoms that no more bonds may be formed

such alkanes.

7 0

4 years ago