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docker41 [41]
2 years ago
15

How do you find out how many protons,electrons, and neutrons an atom has?

Chemistry
1 answer:
Evgen [1.6K]2 years ago
8 0
So the atomic number is the same as protons, and electrons and to get neutrons by subtracting number of protons from atomic mass.
You might be interested in
ANSWER FAST!!
belka [17]

Answer: 800 mL of methyl alcohol should be added to 200 ml of water to make this solution.

Explanation:

Volume of the methyl alcohol = x

Volume of water = y = 200 mL

Volume of the solution ,V = x + y

Volume percentage of solution = 80%

x = 800 mL

800 mL of methyl alcohol should be added to 200 ml of water to make this solution.

4 0
2 years ago
Use the periodic table to identify the element indicated by each electron configuration by typing in the
EleoNora [17]

Answer:

1s22s22p6: Neon (Ne)

1s22s22p63s23p3: Phosphorous (P)

1s22s22p63s23p64s1: Potassium (K)

1s22s22p63s23p64s2(im not sure what 308 is supposed to be): Calcium (Ca)

1s22s22p63s23p64s23d104p65s24d3: there is no pure element that ends 4d3 that I know of so this can either be Zirconium(Zr) if it ends in 4d2 or Niobium (Nb) if it ends in 4d4

Explanation:

you can look at the periodic table and the trends to find the rough idea of where the electron configuration ends, there are helpful articles and images on these, i attached an image that may help. After that you can look at the atomic number to find the number of electrons for a pure element and use the electron subshell pattern thing to find the exact number

5 0
1 year ago
Express in scientific notation. Make sure your answer has the same number of significant figures as the starting value.
frez [133]
The correct response is the second option.
6.1103x10^4. As this was the only answer that had the same number of significant figures as the starting value.
6 0
3 years ago
When metals form ions, they tend to do so by what
In-s [12.5K]
Losing electrons and forming positive ions
5 0
3 years ago
Read 2 more answers
Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h
bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

We know that,

The relation between the C_p\text{ and }C_v for an ideal gas are :

C_p-C_v=R

As we are given :

C_p=28.253J/K.mole

28.253J/K.mole-C_v=8.314J/K.mole

C_v=19.939J/K.mole

Now we have to calculate the entropy change of the gas.

\Delta S=-n\times C_v\ln \frac{T_2}{T_1}

\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. (w=-pdV)

(C) Heat during the process will be,

q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

7 0
3 years ago
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