1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
docker41 [41]
2 years ago
15

How do you find out how many protons,electrons, and neutrons an atom has?

Chemistry
1 answer:
Evgen [1.6K]2 years ago
8 0
So the atomic number is the same as protons, and electrons and to get neutrons by subtracting number of protons from atomic mass.
You might be interested in
Describe three factors that could limit the growth of the prairie dog population
alexira [117]

Answer:

Changes in environment, food source changes and disease?

Explanation:

I dont know what the answer choices are

5 0
3 years ago
Read 2 more answers
7.00 of Compound x with molecular formula C3H4 are burned in a constant-pressure calorimeter containing 35.00kg of water at 25c.
beks73 [17]

Answer:

\Delta H_{f,C_3H_4}=276.8kJ/mol

Explanation:

Hello!

In this case, since the equation we use to model the heat exchange into the calorimeter and compute the heat of reaction is:

\Delta H_{rxn} =- m_wC_w\Delta T

We plug in the mass of water, temperature change and specific heat to obtain:

\Delta H_{rxn} =- (35000g)(4.184\frac{J}{g\°C} )(2.316\°C)\\\\\Delta H_{rxn}=-339.16kJ

Now, this enthalpy of reaction corresponds to the combustion of propyne:

C_3H_4+4O_2\rightarrow 3CO_2+2H_2O

Whose enthalpy change involves the enthalpies of formation of propyne, carbon dioxide and water, considering that of propyne is the target:

\Delta H_{rxn}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{f,C_3H_4}

However, the enthalpy of reaction should be expressed in kJ per moles of C3H4, so we divide by the appropriate moles in 7.00 g of this compound:

\Delta H_{rxn} =-339.16kJ*\frac{1}{7.00g}*\frac{40.06g}{1mol}=-1940.9kJ/mol

Now, we solve for the enthalpy of formation of C3H4 as shown below:

\Delta H_{f,C_3H_4}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{rxn}

So we plug in to obtain (enthalpies of formation of CO2 and H2O are found on NIST data base):

\Delta H_{f,C_3H_4}=3(-393.5kJ/mol)+2(-241.8kJ/mol)-(-1940.9kJ/mol)\\\\\Delta H_{f,C_3H_4}=276.8kJ/mol

Best regards!

7 0
2 years ago
What is the name of this branched alkane?
melamori03 [73]
Branched chain alkanes

The alkanes don't contain a functional group and so the branches are numbered from the end that gives the lowest set of position numbers for the branches.

Use the above rules to see how the names of the alkanes below are built up.

The structure of 2-methylbutane is a butane molecule (C4H10) but with a methyl group (CH3) replacing a hydrogen on the second carbon atom in the chain. The structure of 3-methylpentane could be drawn as butane with an ethyl group (C2H5) replacing a hydrogen on the second carbon. Note that this is not 2-ethylbutane. The structure of 2,2-dimethylbutane is butane with two methyl groups replacing the two hydrogens on the second carbon.
4 0
3 years ago
Assume that the test tube shown started out having 10.00 g of mercury(II) oxide. After heating the test tube briefly, you find 1
anyanavicka [17]

This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.

Initially, it is given a mass of 10.00 g of the oxide and 1.35 g are left which means that the following mass is consumed:

m_{HgO}^{consumed}=10.00g-1.35 g=8.65 g

Now, since 8.00 grams of liquid mercury are collected, it is possible to calculate the grams of oxygen that were produced, by considering the law of conservation of mass, which states that the mass of the products equal that of the reactants as it is nor destroyed nor created. In such a way, the mass of oxygen turns out to be:

m_{O_2}=8.65g-8.00g=0.65g

Learn more:

  • brainly.com/question/14502981
  • brainly.com/question/14236219
3 0
2 years ago
When Xavier places his hands near a light bulb, he notices that certain areas around the light bulb are warmer than others.
Artemon [7]

Answer:

because of conduction. The areas to the sides of the light bulb are warmest because of convection. The area directly above the light bulb is warmest because of conduction. The area directly above the light bulb is warmest because of convection

6 0
3 years ago
Other questions:
  • The following two compounds are constitutional isomers. Identify which of these is expected to be more acidic, and explain your
    14·1 answer
  • Meteors look like they have tails. Are they the same as comet tails?
    8·1 answer
  • Why is it difficult to hold and keep liquids like water in your hand? Guys please help
    6·1 answer
  • What would happen if the earth did not have gravity?
    13·2 answers
  • A cube is 4 cm on each side. What is its volume?<br><br> Answer: 64cm^3
    14·1 answer
  • Why the moon is the barycenter of earth?
    12·1 answer
  • Name the functional group in the
    10·1 answer
  • C6h5-c=o-ch3 + br2/oh
    6·1 answer
  • Which statement is a scientific conclusion?
    10·1 answer
  • How many molecules are in 0.79 moles of NH4?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!