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Umnica [9.8K]
3 years ago
15

Which one of the following classes of organic compound does not contain the carbonyl (C=O) group?A) aldehydesB) carboxylic acids

C) ketonesD) alcoholsE) esters
Chemistry
1 answer:
vredina [299]3 years ago
3 0

Answer: alcohols

Explanation:

The carbonyl group refers to C=O. It is contained in aldehyde, Ketones, carboxylic acids , esters, amides and acyl chlorides. They are not found in alcohols. The alchols are generally ROH. They do not contain any carbon-oxygen unsaturated bond in their structure hence the answer.

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List 4 types of information that are given in each box of the periodic table:
omeli [17]
1) the element symbol, and thus name. For example, H is hydrogen, C is carbon and Fe is iron.

 2) The atomic number, which is equal to the number of protons in the nucleus.

 3) Since each proton has a +1 charge, you can also figure out the number of -1 electrons in the neutral atom.

 4) The atomic mass, in atomic mass units, which is an average of 1 or more isotopes of the element.  
5 0
3 years ago
B. if 6.73 g of na2co3 is dissolved in enough water to make 250. ml of solution, what is the molar concentration of sodium carbo
BARSIC [14]

Answer:- [Na_2CO_3]=0.254M , [Na^+]=0.508 M , [CO_3^2^-]=0.254M

Solution:- We are asked to calculate the molarity of sodium carbonate solution as well as the sodium and carbonate ions.

Molarity is moles of solute per liter of solution. We have been given with 6.73 grams of sodium carbonate and the volume of solution is 250.mL.  Grams are converted to moles and mL are converted to L and finally the moles are divided by liters to get the molarity of sodium carbonate.

Molar mass of sodium carbonate is 105.99 gram per mol. The calculations for the molarity of sodium carbonate are shown below:

\frac{6.73gNa_2CO_3}{250.mL}(\frac{1mol}{105.99g})(\frac{1000mL}{1L})

= 0.254MNa_2CO_3

So, molarity of sodium carbonate solution is 0.254 M.

sodium carbonate dissociate to give the ions as:

Na_2CO_3(aq)\rightarrow 2Na^+(aq)+CO_3^2^-

There is 1:2 mol ratio between sodium carbonate and sodium ion. So, the molarity of sodium ion will be two times of sodium carbonate molarity.

[Na^+]=2(0.254M) = 0.508 M

There is 1:1 mol ratio between sodium carbonate and carbonate ion. So, the molarity of carbonate ion will be equal to the molarity of sodium carbonate.

[CO_3^2^-]=0.254M


5 0
4 years ago
What is rust and why don't we want it floating around in our body
Virty [35]
Rust is when a metal turns brown-ish red-ish and that tells you that the metal is old and is no longer useful. we don't want it floating in our bodies because it's rusted metal. hope this helped! :)

6 0
3 years ago
Each day, the stomach produces 2.0 L of gastric juice that contains 0.10 M HCl. Phillips Milk of Magnesia is a white-colored, aq
trasher [3.6K]

Answer:

It would take 72.9 mL of milk of magnesia.

Explanation:

First of all we have to think how the compounds react with each other and what are the products formed. In this case, the hydrochloric acid reacts with magnesium hydroxide to generate magnesium chloride and water as a subproduct. Having said that, we have to state the balanced chemical reaction to know the associated stoichiometry:

2 HCl + Mg(OH)2 → MgCl2 + 2 H2O

According to the balanced equation we know that 2 mol of HCl reacts with 1 mol of Mg(OH)2.

Now we calculate the quantity of moles of HCl that we have present in 2.0 lts of 0.10 M solution:

0.1 M HCl = 0.1 moles HCl / 1000 ml Solution

So, in 2 liters of solution we will have 0.2 moles of HCl

This 0.2 moles of acid, as we stated before, will react with 0.1 moles of Mg(OH)2, so we need to calculate the amount of milk of magnesia that has this required quantity of moles.

With the molar mass of Mg(OH)2 we calculate the weight of the compound that represents the 0.1 moles needed to react with all the HCl present in solution:

1 mol Mg(OH)2 = 58.32 g

0.1 mol = 5.832 g

Now we need to determine what volume of the milk of magnesia solution has 5.832 g of Mg(OH)2 to react with the acid:

The concentration of milk of magnesia is 8 % (w/v). This means that we have 8 gr of Mg(OH)2 per 100 ml of solution.

8 gr Mg(OH)2 per 100 mL Solution

5.832 gr Mg(OH)2 = 72.9 mL of Milk of Magnesia

6 0
3 years ago
Examples 36
brilliants [131]

2x = 350- x

3x = 350

x = 350/x

therefore,

x = 116.67cm.

so, (350 - x)cm³ = (350- 166.67)cm³ = 233.33cm³

Hence distance covered by gas A is 116.67cm that by B is 233.33cm

5 0
4 years ago
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