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anygoal [31]
3 years ago
10

What number is 8.0007 • 10 ^6 in scientific notation?

Mathematics
2 answers:
leva [86]3 years ago
8 0
8,000,700

Take the decimal and move it six spaces to the right.
Sliva [168]3 years ago
7 0
8.0007*(10*10*10*10*10*10)=8000700

Answer is 8000700

Hope it helped you.

-Charlie
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Which is the best first step to write this in standard form?
goldenfox [79]

Answer:

<em>Set the function equal to 0</em>

Step-by-step explanation:

<u>Standard Form of the Quadratic Equation</u>

The form

ax^2+bx+c=0

is called the standard form of a quadratic equation. It can be clearly identified the terms of a second-degree polynomial equated to 0.

The equation is given in the form:

2(x-4)^2-3=8

And we need to operate the expression to make it look like a standard form. The first logical step should be to set the function equal to 0 and then start to operate the resulting expression. It can be done by subtracting 8 on both sides of the equation:

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Answer: Set the function equal to 0

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3 years ago
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The slope is 3 or 3/1 and the Y intercept is 0 or (0,0) because in y=mx+b, is it the slope (3) and b is the y intercept (0)
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Levart [38]
98 divided by 7


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    7-round to 10

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So 98 divided by 7 is about 10

That is one way

3 0
3 years ago
Help algebra 2 please
kati45 [8]

Answer:

Step-by-step explanation:

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        = - 5x³ + <u>2x² -5x²</u>   <u>+ 7x + 2x </u>+7   {Combine like terms}

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2) Speed=\dfrac{distance}{time}\\\\\\= \dfrac{d(h)}{t(h)}\\\\= \dfrac{2\sqrt{h}}{3\sqrt{4h}}=\dfrac{2*\sqrt{h}}{3*2\sqrt{h}}\\\\\\=\dfrac{1}{3}

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7 0
3 years ago
For each system of equations, drag the true statement about its solution set to the box under the system?
natta225 [31]

Answer:

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

Step-by-step explanation:

* Lets explain how to solve the problem

- The system of equation has zero number of solution if the coefficients

 of x and y are the same and the numerical terms are different

- The system of equation has infinity many solutions if the

   coefficients of x and y are the same and the numerical terms

   are the same

- The system of equation has one solution if at least one of the

  coefficient of x and y are different

* Lets solve the problem

∵ y = 4x + 2 ⇒ (1)

∵ y = 2(2x - 1) ⇒ (2)

- Lets simplify equation (2) by multiplying the bracket by 2

∴ y = 4x - 2

- The two equations have same coefficient of y and x and different

  numerical terms

∴ They have zero equation

y = 4x + 2

y = 2(2x - 1)

Zero solutions.

4x + 2 can never be equal to 4x - 2

∵ y = 3x - 4 ⇒ (1)

∵ y = 2x + 2 ⇒ (2)

- The coefficients of x and y are different, then there is one solution

- Equate equations (1) and (2)

∴ 3x - 4 = 2x + 2

- Subtract 2x from both sides

∴ x - 4 = 2

- Add 4 to both sides

∴ x = 6

- Substitute the value of x in equation (1) or (2) to find y

∴ y = 2(6) + 2

∴ y = 12 + 2 = 14

∴ y = 14

∴ The solution is (6 , 14)

y = 3x - 4

y = 2x + 2

One solution

3x - 4 = 2x + 2 has one solution

3 0
3 years ago
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