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2 years ago

Shade the cenn diagram to represent the set

Mathematics

1 answer:

Elena-2011 [213]2 years ago

5 0

Look at the pictures.

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Use the factorization to find the values of x for which p(x) = 0. (x – 1)(x 1)(x 5) = 0 x – 1 = 0, so x = x 1 = 0, so x = x 5 =

Sladkaya [172]

Answer: (x – 1)(x + 1)(x + 5) = 0

x – 1 = 0, so x = 1

x + 1 = 0, so x = -1

x + 5 = 0, so x = -5

3 0

1 year ago

Not understanding how to solve

valentinak56 [21]

Answer:16x-4. You add all the numbers with common terms first, such as all the xs together. Then you add all the numbers without an x in front and tada!

Step-by-step explanation:Above

5 0

2 years ago

If (x, y) is a solution to the system of equations, what is the value of y? 1/4 x + 1/8 y = 2 1/3 x + 1/2 y = 4 A) 4 B) 6 C) -6

andre [41]

<h3>The value of y is 4</h3>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

$\frac{1}{4}x + \frac{1}{8}y =2 ---------- eqn\ 1\\\\\frac{1}{3}x + \frac{1}{2}y = 4 -------------- eqn\ 2$

We have to find value of y

From eqn 1,

$\frac{1}{4}x + \frac{1}{8}y =2 \\\\2x + y = 2 \times 8\\\\2x + y = 16 ---- eqn\ 3$

From eqn 2,

$\frac{1}{3}x + \frac{1}{2}y = 4\\\\2x + 3y = 4 \times 6\\\\2x + 3y = 24 ------ eqn\ 4$

Subtract eqn 3 from eqn 4

2x + 3y = 24

2x + y = 16

( - ) -----------------

2y = 8

y = 4

Thus value of y is 4

5 0

2 years ago

2 children share 2 small boxes of cereal

adelina 88 [10]

Each person would get 1 bix of cereal because 2 divided by 2 = 1

Hope that helps!!! ;)

6 0

3 years ago

A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi

Margaret [11]

Answer:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=26Kg$

Step-by-step explanation:

Data

Brine a (Ba)

$V_{Ba}=5\frac{Lt}{min}\\ Concentration(Bca)=0.05\frac{Kg}{Lt}$

Brine b (Bb)

$V_{Bb}=10\frac{Lt}{min}\\ Concentration(Bcb)=0.04\frac{Kg}{Lt}$

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: $y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}$

Finally:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=0.65\frac{Kg}{min}(40min)=26Kg$

being y(t) the amount of salt (y) per unit of time (t)

5 0

2 years ago