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3 years ago

Shade the cenn diagram to represent the set

Mathematics

1 answer:

Elena-2011 [213]3 years ago

5 0

Look at the pictures.

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Convert the repeating decimal to a fraction

lilavasa [31]

17. 2/3
18. 1 1/9
20.9 1/11
21. 2 909/100 (closest i could get)
Hope I helped and hope you had a good day!

6 0

3 years ago

Can someone help??.?.

Butoxors [25]

Answer: 8/100

Step-by-step explanation: I converted 5/10 in 50/100 and subtracted 50 from 58 and got 8 so the answer is 8/100.

8 0

3 years ago

Read 2 more answers

The dance committee of Pine Bluff Middle School earns \$72$72 from a bake sale and will earn \$4$4 for each ticket they sell to

jeyben [28]

Answer:

Inequality is $4t+72>400$

Solution is C: t > 82

Step-by-step explanation:

Let the number of tickets = t

It is given that the committee earns $4 per ticket. That is, they earn $4t$ dollars.

Also, the committee earns $72 from the bake sale.

So, the total income is $4t+72$ dollars.

Since, the dance will cost $400.

So, the total earning must be greater than $400.

Thus, the inequality for the situation is given by, $4t+72>400$ .

So, on solving, we have,

$4t+72>400$

i.e. $4t>328$

i.e. t > 82.

Thus, the solution of the inequality is $t> 82$

Hence, option C is correct.

6 0

3 years ago

Read 2 more answers

How do you solve this I need to solve for x and I also need 20 characters to send this so her you go

g100num [7]

Answer:Exact Form:

−

Decimal Form:

−

1.5

Mixed Number Form:

−

6 0

3 years ago

Lim x approaches 0 (1+2x)3/sinx

jok3333 [9.3K]

Interpreting your expression as

$\dfrac{3(1+2x)}{\sin(x)}$

when $x$ approaches zero, the numerator approaches 3:

$3(1+2x) \to 3(1+2\cdot 0) = 3(1+0) = 3\cdot 1 = 3$

The denominator approaches 0, because $\sin(0)=0$

Moreover, we have

$\displaystyle \lim_{x\to 0^-} \sin(x) = 0^-,\quad \displaystyle \lim_{x\to 0^+} \sin(x) = 0^+$

So, the limit does not exist, because left and right limits are different:

$\displaystyle \lim_{x\to 0^-} \dfrac{3(1+2x)}{\sin(x)}= \dfrac{3}{0^-} = -\infty,\quad \displaystyle \lim_{x\to 0^+}\dfrac{3(1+2x)}{\sin(x)}= \dfrac{3}{0^+} = +\infty$

8 0

3 years ago