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3 years ago

Montrell saves 8% of each paycheck for his college fund. This week he saved $18.80 from his paycheck, how much was he paid?

Mathematics

1 answer:

castortr0y [4]3 years ago

8 0

8% of x = $18.80
x = 18.80/8%
x = 18.80/0.08
x = $235

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Translate the verbal expression "Five less than the product of X and three" into an algebraic expression

Illusion [34]

Answer:

x+3-5 i think

Step-by-step explanation:

"and" means add so x+3 and subtract 5

6 0

3 years ago

Drag and drop each expression into the box to correctly classify it as having a positive or negative product

AfilCa [17]

Following expressions will have negative product

$(\frac{1}{2})(-\frac{1}{2})\ and\ (-\frac{1}{2})(\frac{1}{2})$

Following expressions will have positive product

$(-\frac{1}{2})(-\frac{1}{2})\ and\ (\frac{1}{2})(\frac{1}{2})$

Further explanation:

We will see at each expression one by one

First expression is:

$(-\frac{1}{2})(\frac{1}{2})$

In the given expression one term is positive and one term is negative. The product of negative and positive terms is negative.

Second Expression is:

$(-\frac{1}{2})(-\frac{1}{2})$

Both terms are negative and the product of two negative terms is positive.

Third Expression is:

$(\frac{1}{2})(-\frac{1}{2})$

The expression has one positive and one negative term so the product will be negative

Fourth Expression is:

$(\frac{1}{2})(\frac{1}{2})$

Both terms are positive so the product will also be positive

Keywords: Product, Expressions

Learn more about expressions at:

#LearnwithBrainly

5 0

4 years ago

Do anyone know how to answer this?

ANTONII [103]

Answer:

Step-by-step explanation:

8 0

3 years ago

What is the antiderivative of 3x/((x-1)^2)

Maslowich

Answer:

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Step-by-step explanation:

Given

$\int \:\:3\cdot \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx$

$=3\cdot \int \frac{x}{\left(x-1\right)^2}dx$

$\mathrm{Apply\:u-substitution:}\:u=x-1$

$=3\cdot \int \frac{u+1}{u^2}du$

$\mathrm{Expand}\:\frac{u+1}{u^2}:\quad \frac{1}{u}+\frac{1}{u^2}$

$=3\cdot \int \frac{1}{u}+\frac{1}{u^2}du$

$\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx$

$=3\left(\int \frac{1}{u}du+\int \frac{1}{u^2}du\right)$

$\int \frac{1}{u}du=\ln \left|u\right|$ ∵ $\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)$

$\int \frac{1}{u^2}du=-\frac{1}{u}$ ∵ $\mathrm{Apply\:the\:Power\:Rule}:\quad \int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1$

$=3\left(\ln \left|u\right|-\frac{1}{u}\right)$

$\mathrm{Substitute\:back}\:u=x-1$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)$

$\mathrm{Add\:a\:constant\:to\:the\:solution}$

$=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

Therefore,

$\int \:3\cdot \frac{x}{\left(x-1\right)^2}dx=3\left(\ln \left|x-1\right|-\frac{1}{x-1}\right)+C$

4 0

3 years ago

10) Use the graph below: What percent of strikeouts is Samar responsible 10 pointsfor?BASEBALL STRIKEOUTSCARLOSPITCHERYUSAMARJUS

JulsSmile [24]

First let's find out the total number of strikeouts, by adding the number of strikeouts of each person:

$\text{total}=13+9+5+11+8+4=50$

Now, to find the percentage of strikeouts that Samar is responsible, let's divide his number of strikeouts (5) by the total number of strikeouts (50):

$\frac{5}{50}=\frac{1}{10}=\frac{10}{100}=10\text{\%}$

So Samar is responsible for 10% of the strikeouts.

4 0

1 year ago