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3 years ago

Which expression is equivalent to (2mn)4/6m^-3n^-2

Mathematics

2 answers:

Rzqust [24]3 years ago

7 0

Answer: 8m^7n^6/3

Step-by-step explanation:

Scrat [10]3 years ago

4 0

Answer is the option 1
Because the denominator is 6/

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The cost of a bag of 8 peaches is $16. You could also buy individual peaches for

Veronika [31]

Answer: The peaches sold in bags

Step-by-step explanation:

16/8=2 This means that a single peach in the bag of peaches is worth $2. This is $0.15 cheaper than buying a single peach

The unit rte for a single peach is $2.15

The unit rate for a single peach in the bag of peaches is $2

5 0

3 years ago

Ill Mark Brainliest if you answer correctly. The figure below shows a shaded circular region inside a larger circle:

pogonyaev

First we have to find the areas of both circle using the formula

$Area = \pi r^2$

For larger circle,

$Area= \pi(5)^2 = 25 \pi$

For smaller circle,

$Area = \pi (4)^2 = 16 \pi$

Required probability

$= \frac{25 \pi -16 \pi}{25 \pi} *100 = \frac{9}{25}*100 = 36%$

Correct option is the second option .

8 0

3 years ago

in the morning , Emily studied 40 minutes for an exam. Later that evening, Emily studied for x more minutes. write an equation t

julia-pushkina [17]

Answer:

40 + x = y

Just use the variables given to make an equation.

3 0

3 years ago

Read 2 more answers

Un jardín rectangular de 50 cm de largo por 34 m de ancho está rodeado por un camino de arena uniforme.Halla la anchura de dicho

Anastasy [175]

Answer:

5.85 m

Step-by-step explanation:

The width of the sand road can be calculated knowing its area and the dimensions of the rectangular garden as follows:

$A_{g} = a.b$

<u>Where:</u>

Ag: is the area of the rectangular garden

a: is the length of the rectangular garden = 50 cm = 0.5 m

b: is the width of the rectangular garden = 34 m

$A_{s} = 540 m^{2}$

<u>Where</u>:

As: is the area of the sand road

The relation between the area of the sand road and the area of the rectangular garden is the following:

$A_{s} + A_{g} = (a+2x)*(b+2x)$

$540 m^{2} + 0.5m*34m = ab + 2ax + 2bx + 4x^{2}$

$557 m^{2} = ab + 2x(a + b) + 4x^{2}$

$557 m^{2} - 17m^{2} - 2x(34.5 m) - 4x^{2} = 0$

$540 - 69x - 4x^{2} = 0$

By solving the above equation for x we have two solutions:

x₁ = -23.10 m

x₂ = 5.85 m

Taking the positive value, we have that the width of the sand road is 5.85 m.

I hope it helps you!

7 0

3 years ago

What is e area of the trapezoid?

Korvikt [17]

Answer:

Step-by-step explanation:

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3 0

3 years ago