Great White
White-angled sulphur
Large orange sulphur
Apricot sulphur
I hope this helps you
7r^2+6r-16
7r -8
r +2
(7r-8)(r+2)
Answer:
C) 3 times the sq root of 3
Step-by-step explanation:
In a right angle triangle, the COS is definned as the ajacent side over the hypotenuse. So
COS 60 = JK/JL
COS 60 = JK/(6*sq root 3)
.5 = JK/(6*3**1/2)
JK = .5 *(6*3**1/2)
JK = 3*3**1/2