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Aleksandr [31]
3 years ago
13

Find the sum of 3 2/5 + 1 4/5

Mathematics
2 answers:
Ivanshal [37]3 years ago
7 0

Answer:

5 1/5

Step-by-step explanation:

When adding mixed fractions, add the number and the fraction separately.

2/5 + 4/5 = 6/5 = 1 1/5

3 + 1 = 4

Once you add it separately, add the two sums together.

4 + 1 1/5 = 5 1/5

Charra [1.4K]3 years ago
3 0
3 2/5 + 1 4/5 = 5 1/5
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Exponential growth and decay functions are written in standard form F (t)= A_0•b^kt, where A_0 is an initial amount, b is the gr
tia_tia [17]
t is the time elapsed since the concentration was the A_=, this is the initial concentration.

For example, for A_0 = 250, k = -10 (it has to be negative because this is a decay function) and b = 24, the function will be:

F(t) = 250 *  24 ^ (- 10 t)

And so, given that t is the time, you have the relation that gives the value of the dependent variable as a function of the time t. If the unit is hours, you could make this table:

time, t in hours             F(t) = 250 * 24 ^ ( -10t)

0                                   250 * 24 ^(0) = 250

0.01                              250 * 24 ^ (- 10 * 0.01) ≈ 0.73

0.1                                250 * 24 ^ (-10* 0.1) ≈ 0.042

1                                  250 * 24 ^ ( -10) ≈ 0.000000000000016
5 0
3 years ago
Read 2 more answers
Hello, I need help. thank you
Nimfa-mama [501]

Answer:

B

Step-by-step explanation:

all you need to do is add 5 to the y for example ( -5, 5) add 5 to the (x,5) to make ( -5,10). As you can see only the y value is shifting, not the x value, that's why you need to add 5 to all the y values.

So the answer here is B.

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2 years ago
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creativ13 [48]

Answer:

(-3, -4)

Step-by-step explanation:

The solution is where the two lines intersect. Therefore, the x-coordinate is -3, and the y-coordinate is -4.

Another way to solve this would be to set the to equations equal to each other, so 2x+2 = -4. Therefore, 2x = -6, and x = -3. And from the second equation, y = -4.

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3 years ago
Consider the function below. f(x)= x^3 + 2x^2 - x - 2 plot the x and y intercepts of the function
dimulka [17.4K]

In the Figure below is shown the graph of this function. We have the following function:

f(x)=x^3+2x^2-x-2

The y-intercept occurs when x=0, so:

f(0)=(0)^3+2(0)^2-(0)-2=-2

Therefore, the y-intercept is the given by the point:

\boxed{(0,-2)}

From the figure we have three x-intercepts:

\boxed{P_{1}(-2,0)} \\ \boxed{P_{2}(-1,0)} \\ \boxed{P_{3}(1,0)}

So, the x-intercepts occur when y=0. Thus, proving this:

f(x)=x^3+2x^2-x-2 \\ \\ For \ P_{1}:\\ If \ x=-2, \ y=(-2)^3+2(-2)^2-(-2)-2=0 \\ \\ For \ P_{2}:\\ If \ x=-1, \ y=(-1)^3+2(-1)^2-(-1)-2=0 \\ \\ For \ P_{3}:\\ If \ x=1, \ y=(1)^3+2(1)^2-(1)-2=0

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f = gmn/d²

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