The correct question is
<span>What is the equation of a line, in general form, that passes through point (1, -2) and has a slope of 1/3
</span>
we have that
point (1,-2)
slope m=1/3
so
y-y1=m*(x-x1)-----> y+2=(1/3)*(x-1)----> multiply by 3---> 3y+6=x-1
x-3y-1-6=0------> x-3y-7=0
the answer is
<span>x - 3y - 7 = 0</span>
Could possibly be a geyser
Step-by-step explanation:
hope this may help you tq have a nice day
Answer:
1.
Step-by-step explanation:
1. sin 241 = sin(61 + π) = -sin61 = -t^(1/2)
2. sin^2 + cos^2 =1, cos 61= (1-t)^(1/2)
3. [2sin^2 (x)sin(x) +2cos^2 (x)sin(x)]/2cos(x) = 2sin(x) / 2cos(x) = tan(x)
4. tan (x), x do not equal to （π/2 +or- kπ）
x do not equal to 90，270。
