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3 years ago

If a 4-pound roast takes 150 minutes to cook, how long should a five-pound roast take

Mathematics

2 answers:

Ber [7]3 years ago

6 0

188 minutes (rounded) or 187 minutes and 5 seconds

viktelen [127]3 years ago

4 0

First divide 150 with 4
150/4 = 37.5
Then you have to multiply 37.5 with 5
37.5 * 5 = 187.5
So it will take 187.5 to roast!!
Hope This Helps!!

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The mass of a certain window is 18kg. What is the mass of 5 of those windows?

Daniel [21]

18 kg times 5 kg would be 90 kg because each window was 18 kg, hence 90 kg

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3 years ago

What is the best approximation for the circumference of a circle with a radius of 125 m?

ANEK [815]

Answer:

Option B is correct

circumference of a circle is 785 m

Step-by-step explanation:

Circumference of the circle(C) is given by:

$C = 2\pi r$

where

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As per the statement:

radius of the circle is 125 m

then substitute in [1] we have

$C = 2 \cdot 3.14 \cdot 125$

Simplify:

C = 785 m

Therefore, the circumference of a circle is 785 m

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3 years ago

Read 2 more answers

This will take the smartest brainly player<br> Give explanation

ratelena [41]

Answer:

n^6 is the answer

$n^{6} * n^{\frac{1}{4} } = n^{\frac{25}{4} }$

$\frac{1}{\sqrt[4]{n} } * n^{\frac{25}{4} } = \frac{n^{\frac{25}{4} } }{n^{\frac{1}{4} } } = n^{\frac{25}{4} } - n^{\frac{1}{4} } = n^{6}$

Step-by-step explanation:

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3 years ago

Plz help! Will give brainlest

AnnZ [28]

Answer:

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Step-by-step explanation:

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2 years ago

A parabola can be drawn given a focus of (-5, -4)(−5,−4) and a directrix of y=-6y=−6. Write the equation of the parabola in any

lord [1]

Answer:

$\displaystyle \large{y=\dfrac{x^2}{4} + \dfrac{5x}{2} + \dfrac{5}{4}}$

Step-by-step explanation:

Given:

Focus = (-5,-4)
Directrix = -6

To find:

Parabola Equation

Locus of Parabola (Upward/Downward)

$\displaystyle \large{\sqrt{(x-a)^2+(y-b)^2} = |y-c|}$

Where:

(a,b) = focus
c = directrix

Hence:

$\displaystyle \large{\sqrt{(x+5)^2+(y+4)^2}=|y+6|}$

Cancel square root by squaring both sides as we get:

$\displaystyle \large{(x+5)^2+(y+4)^2=(y+6)^2}$

Solve for y-term:

$\displaystyle \large{(x+5)^2=(y+6)^2-(y+4)^2}\\\displaystyle \large{x^2+10x+25=y^2+12y+36-y^2-8y-16}\\\displaystyle \large{x^2+10x+25=4y+20}\\\displaystyle \large{x^2+10x+5=4y}\\\displaystyle \large{y=\dfrac{x^2}{4} + \dfrac{5x}{2} + \dfrac{5}{4}}$

4 0

2 years ago