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S_A_V [24]
3 years ago
5

In a random sample of microwave​ ovens, the mean repair cost was ​$ and the standard deviation was ​$. Using the standard normal

distribution with the appropriate calculations for a standard deviation that is​ known, assume the population is normally​ distributed, find the margin of error and construct a ​% confidence interval for the population mean μ. A 98​% confidence interval using the​ t-distribution was (687,913). Compare the results.
The margin of error of μ is:_______
Mathematics
1 answer:
Semmy [17]3 years ago
7 0

Complete Question

In a random sample of 13 microwave ovens, the mean repair cost was $90.00 and the standard deviation was $15.20. Using the standard normal distribution with the appropriate calculations for a standard deviation that is known, assume the population is normally distributed, find the margin of error and construct a 98% confidence interval for the population mean u. A 98% confidence interval using the t-distribution was (78.7,101.3). Compare the results. The margin of error of u is

Answer:

The value  is  E = 11.65

Step-by-step explanation:

From the question we are told that

    The sample is  n  = 13

     The sample mean is  \= x  =  \$ 90

     The standard deviation is  \sigma = \$ 15.20

      The  lower limit of the  98% confidence interval is a =  78.7

      The  upper  limit of the  98% confidence interval is b =  101.3

Generally the margin of error is mathematically represented as

        E = \frac{b-a}{2}

=>    E = \frac{ 101.3 - 78 }{2}

=>    E = 11.65

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