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just olya [345]
3 years ago
8

Given that 2x + 7 = 27 and 3x + 1 = 28 does 2x + 7 = 3x + 17 brainliest

Mathematics
1 answer:
Gemiola [76]3 years ago
8 0
No They are not equal to each other.


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67.498 to the nearest whole number
insens350 [35]

Answer:

67

Step-by-step explanation:

To round 67.498 to the nearest whole number consider the tenths’ value of 67.498, which is 4 and less than 5. Therefore, we have to round down: the whole number ones place value of 67.498, 67, remains 67, and the decimal point and all digits (.498) are removed.

67.498 rounded to the nearest whole number = 67

8 0
3 years ago
Determine which two values the following number is between. A. 12 and 13 B. 13 and 14 C. 15 and 16 D. 14 and 15
nordsb [41]

Answer:

more info pls

Step-by-step explanation:

8 0
3 years ago
Question 6 of 15
umka2103 [35]

Answer:

LE=5\ units

Step-by-step explanation:

we know that

In a rectangle, the two diagonals are congruent and each diagonal bisects the other

so

LN=2KE ----> equation A

KE=LE -----> equation B

step 1

Find the value of x

solve equation A

LN=2KE

substitute the given values

(2x+2)=2(3x-7)

solve for x

2x+2=6x-14\\6x-2x=2+14\\4x=16\\x=4

step 2

Find the value of KE

KE=3x-7

substitute the value of x

KE=3(4)-7=5\ units

Remember that

KE=LE  -----> by each diagonal bisects the other

therefore

LE=5\ units

8 0
3 years ago
EX 1) Games Galore Super Store buys the latest video game at a wholesale price of $30.00. The markup rate at Game's Galore Super
nataly862011 [7]

Answer:

$42

Step-by-step explanation:

Given that,

Galore Super Store buys the latest video game at a wholesale price of $30.00.

The markup rate at Game's Galore Super Store is 40%.

We need to find the price from the store. It can be calculated as follows :

C=30+\dfrac{40}{100}\times 30\\\\=30+12\\\\=\$42

Hence, we will pay $42.

3 0
3 years ago
Find the average value of f over region
yan [13]
The area of D is given by:

\int\limits \int\limits {1} \, dA = \int\limits_0^7 \int\limits_0^{x^2} {1} \, dydx  \\  \\ = \int\limits^7_0 {x^2} \, dx =\left. \frac{x^3}{3} \right|_0^7= \frac{343}{3}

The average value of f over D is given by:

\frac{1}{ \frac{343}{3} }  \int\limits^7_0  \int\limits^{x^2}_0 {4x\sin(y)} \, dydx  = -\frac{3}{343}  \int\limits^7_0 {4x\cos(x^2)} \, dx  \\  \\ =-\frac{3}{343} \int\limits^{49}_0 {2\cos(t)} \, dt=-\frac{6}{343} \left[\sin(t)\right]_0^{49} \, dt=-\frac{6}{343}\sin49
3 0
3 years ago
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