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ANEK [815]
3 years ago
11

Which expression is equivalent to 7√x^2/5√y^3? Assume y≠0

Mathematics
1 answer:
ella [17]3 years ago
7 0

Answer:

Step-by-step explanation:

If the √y³ term is in the denominator, then the expression needs to be written with parentheses:  7√x²/(5√y³)

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A juggler perform in a telant contest. He is given 10 marks by each of the 4 judges. What’s his total score?
Mars2501 [29]

Answer:

40

Step-by-step explanation:

The answer is 40. There are 4 judges, and each gave him a 10. This can be shown by an equation.

1. 4 * 10 = total score

2. 40 = total score.

Hope this helps! (Please consider giving brainliest)

6 0
3 years ago
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Can someone please help me
gtnhenbr [62]

Answer:

1) B) 10

2) B) 9

Step-by-step explanation:

1) 10x+15=115

10x=100

x=10

2) 12x+17=125

12x=108

x=9

8 0
3 years ago
351 students in 27 classes _____ students in each class
77julia77 [94]

Answer:

13

Step-by-step explanation:

351 divided by 27 = 13

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2 years ago
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valentina_108 [34]
The median is 10.5 because its the middle line in the box and all you have to do is look at it and you can see it
8 0
3 years ago
Evaluate................
wolverine [178]

Answer:

h(8q²-2q) = 56q² -10q

k(2q²+3q) = 16q² +31q

Step-by-step explanation:

1. Replace x in the function definition with the function's argument, then simplify.

h(x) = 7x +4q

h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q

__

2. Same as the first problem.

k(x) = 8x +7q

k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q

_____

Comment on the problem

In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...

h(8q² -2q) = 56q² -14q +4z

and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.

In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.

7 0
3 years ago
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