Ask question

Ask question

All categories

2 years ago

9

Solve the following equation using the liquid liquid associative property use the following charts to determine wheather this is

rational or irrational

2 answers:

kari74 [83]2 years ago

8 0

Answer:

is is to be assumed that the equation is rational

Step-by-step explanation:

adell [148]2 years ago

6 0

Hmm this seem rather complicated would you send me more details

You might be interested in

Can an equation have equal expressions

Alona [7]

Yes it can have equal expressions

4 0

3 years ago

Diana has just begun the process of filing her federal income tax return, and she plans to deduct medical and dental expenses. w

Andru [333]

Answer:

1040 tehyimngtumh

Step-by-step explanation:

Apex

5 0

2 years ago

Find the missing side lengths

timama [110]

since this a 45 45 90 right triangle to get the side lengths you divide 2 times the square root of 2 and you get 2, since this has two congruent angles which makes it an Isosceles triangle. your a and b value are 2.

8 0

3 years ago

What is the value of x in the figure at the right

alina1380 [7]

We can know from the pic
2x+38=90
so, x=26

6 0

3 years ago

[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation

irina1246 [14]

Answer:

$y=-\frac{158}{579}$

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

$A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]$

And the vector B is formed with the solution of each equation of the system: $b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]$

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called $A_{2}$ .

$A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]$

The value of y using Cramer's rule is:

$y=\frac{det(A_{2}) }{det(A)}$

Find the value of the determinant of each matrix, and divide:

$y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}$

$y=-\frac{158}{579}$

7 0

3 years ago